\text { a. The Base Voltage }=\frac{R b 2}{R b 1+R b 2} * V c c=\frac{8}{48+8} * 12=1.714 \text { Volt } As Vbe =0.7 Volt Emitter voltage =

Base voltage -0.7 =1.014Volt Emitter current = emittervoltage/ emitter resistance=1.014-300=3.38 ma Collector Current =3.38mA Collector Voltage=VCC -lc Rc12 -3.38*1.6 =6.592V VCE=Collector Voltage -Emitter Voltage :6.592 -1.014 =5.578 Volt b. DC load line c. AC load Iline d. The main difference between ac load line and dc load line is that the difference in ac load and dc load are different due to the type of voltage applied and the ac load line exists around the Q point.