\text { The limit } \lim _{x \rightarrow \infty} 7 x e^{5 x}=\lim _{x \rightarrow \infty} \frac{7 x}{e^{-5 x}}=\lim _{x \rightarrow \infty} \frac{7}{-5 e^{-5 x}} \quad \text { using the

L'Hospital's Rule. } O TRUE O FALSE