Question The distance from the center of the breastbone to a man's hand, with the arm outstretched and horizontal to the floor, is 1.00 m. The man is holding a 8.41-kg dumbbell, oriented vertically, in his hand, with the arm horizontal. What is the torque due to this weight about a horizontal axis through the breastbone perpendicular to his chest? The radius of a wheel is 0.740 m. A rope is wound around the outer rim of the wheel. The rope is pulled with a force of magnitude 5.00 N, unwinding the rope and making the wheel spin CCW about its central axis. Ignore the mass of the rope.