The field between the plates is a linearly polarized (in the y direction) uniform plane wave traveling in the z direction. (a) Assume that the plates are perfect electric conductors.

Then find the E and H field components between the plates. Neglect the edge effects of the finite plates. Referring to the figure shown below. (b) Find the separation d between the plates that creates resonance. (c) Derive an expression for the Q of the cavity assuming a conductivity of o for the plates.Neglect any radiation losses through the sides of the cavity. (d) Compute the Q of the cavity when f = 60 GHz and d = 51 and 102. Assume a plate conductivity of o = 5.76 × 107 S/m.