(b) What is the probability that the width of the casing minus the width of the door exceeds 1/3 inch? (c) What is the probability that the door does not

fit in the casing? (a) Determine the mean and standard deviation of the difference between the width of the casing and the width of the door. Mean=___________. Standard deviation=__________. The width of a cosina for a door is normally distributed with a mean of 24 inches and a standard deviation of 1/8 inch. The width of a door is normally distributed with a mean of 23 and 7/6 inches and a standard deviation of 1/16 inch. Assume independence. Round your answers to three decimal places (e.a. 98. 765).