Use variation of parameters to find a general solution to the differential equation given that the

functions y₁ and y₂ are linearly independent solutions to the corresponding homogeneous equation

for t > 0.

ty"' + (2t - 1)y' - 2y = 9t²e-2t.

A general solution is y(t) =

Y₁ = 2t - 1,

Y₂ = e

-2t