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Using Laplace transform to solve the IVP: y^{\prime \prime}+9 y=e^{-3 t}, \quad y(0)=0, \quad y^{\prime}(0)=0 we find the solution y(t)=\mathcal{L}^{-1}\left\{\frac{1}{(s-3)\left(s^{2}+9\right)}\right\}

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