Question

Vector A has a magnitude of 235 N and coordinate direction angles of a = 132°, B = 65°, and y = 52°.Vector B has a magnitude of 20 N and coordinate direction angles of a = 50°, B = 125°, and y = 59°.What is A x B ? \begin{array}{l} \{2683 i-240 j+527 k\} \mathrm{N} \\ \{-882 i-2630 j-3512 k\} \mathrm{N} \\ \{2683 i+3480 j+527 k\} \mathrm{N} \\ 236 \mathrm{~N} \\ -1670 \mathrm{~N} \end{array}

Fig: 1

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