What is the difference of this amplitude and the amplitude for the small time constant? and why there is a difference?. V_{C}=0.31+/-0.05 \text { volts } Because the 10K ohm

resistor decreases the current. \mathrm{V}_{\mathrm{C}}=0.31+/-0.05 \text { volts } Because the resistance of the capacitor changes with the frequency \text { c. } V_{C}=0.31+/-0.05 \text { volts } Because the time constant is as large as the frequency, hence the capacitor is never fully charged in the cycle. V_{C}=3.1+/-0.05 \text { volts } Because the time constant is as large as the frequency, hence the capacitor is fully charged in the cycle.