Question

What is the solution for the differential equation: \frac{d y}{d x}+4 . y=e^{-6 . x} It is given that at the point x = 0, y = 0.3. All decimals

have been given to 2 significant figures. \text { ○ } y=(-0.50) \cdot e^{-6 \cdot x}+(-0.20) \cdot e^{-4 \cdot x} \bigcirc y=(-0.50) \cdot e^{-6 . x}-(0.80) \cdot e^{-4 . x} \bigcirc y=(0.80) \cdot e^{-6 . x}+(-0.50) \cdot e^{-4 . x} y=(-0.50) \cdot e^{-6 . x}+(0.80) \cdot e^{-4 . x}

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