1)The electric field through the closed surface of the cube shown below is described by the following expression, \vec{E}=E_{0}\left(1+\frac{x}{a}\right) \vec{i}+E_{0}\left(\frac{x}{a}\right) \vec{j} where, E, is a constant and a is the

side of the cube. The cube has its sides parallel to the coordinate axes, as seen in the figure. This problem must be worked out in unit-vector notation. In terms of E, and a, work out an expression for the electric flux through the(a)front- and back-side of the cube, respectively. (b)then top- and bottom-side of the cube.Work out an expression for the electric flux through the right-, and left-, and (c)Determine how much charge there is within the cube.