[25 minutes] 9.5 [20 points] Q11 012 V, V10 8 k 8 k 17.2 k +5V V₂ 18 k 18 k -V6 lo V₁ -5V Figure 9.5.1 [10 points] (a) For the circuit in Fig. 9.5.1 (refer to Figure above), assuming VBgl 0.7 V, Boo (i.e., ignoring base currents), and Voo (i.e., ignor- ing the Early effect), find the de values of the labelled currents and voltages. [5 points] (b) If the bases of Q6 and Q are disconnected from ground and a differential input signal vid is applied, find the differential gain if the output is taken between the two collectors. [5 points] (c) Repeat (b) for the differential amplifier (11.212). [30 minutes] 9.6 [28 points] +1 V 24 In the circuit of Fig. 9.6.1, all transistors are matched with kn=kp = 2 mA/V², 1] = 0.4V, and || 10 V. (a) If G1 G2 =0V, find the de bias current in [6 points] cach of the four transistors Q1, 22, 23, and Q4, as well as the overdrive voltage Vorl for each. Ignore the Early effect. Also, find the de voltage at the sources of Q and Q2, as well as the de voltage at the gates of Q3 and Q4. (b) Find gm of each of Q1 and Q2, and determine [4 points] To of cach of Q2 and 24. (c) If GI +/2 and 2/2, find the [3 points] differential gain Ad=vo/d (d) Find the output resistance Rss of the bias- [10 points] current source Qs and use it to determine the common mode gain Acm in the case GI = "G2 = Vicm Also, find the CMRR in dB. (e) If it is required to increase the CMRR by 6 dB, [5 points] by what factor should the channel length of Qs be changed? -1V Figure 9.6.1 80 μA

Solved: [25 minutes] 9.5 [20 points] Q11 012 V, V10 8 k 8 k 17.2 k +5V V₂ 18 k

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25 minutes 9 5 20 points q11 012 v v10 8 k 8 k 17 2 k 5v v 18 k 18 k v

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[25 minutes] 9.5 [20 points] Q11 012 V, V10 8 k 8 k 17.2 k +5V V₂ 18 k 18 k -V6 lo V₁ -5V Figure 9.5.1 [10 points] (a) For the circuit in Fig. 9.5.1 (refer to Figure above), assuming VBgl 0.7 V, Boo (i.e., ignoring base currents), and Voo (i.e., ignor- ing the Early effect), find the de values of the labelled currents