3) A single-phase transformer has the following parameters:

N₁

= 10; Req = R₁ + R₂ = 1; Xeq = X₁ + X₂ = 100; R₁ = 10002; Xo = 5000.2

N₂

The rated voltage of the primary winding is 1000 V. A 0.5230° load is connected across the

secondary terminals. Compute the load voltage.

ZL:

12:

V₂:

V₂:

Z₁ = ZL (N)² = 50 2

The current I, is

V₁

I'₂

(Req+jXeq) +Z₁

(1+510)+50/30*

The load voltage refereed to the primary side V₂' is

V₂ = I₂Z = (17.7/- 38.31°) (50/30°) = 885/ – 8.31° V

Use Equation 11.50 to compute the actual voltage across the load

V₂ = V₂N -885= 88.5 V

2.5 points

5 points

5 points

2.5 points

1000/0

17.7/-38.31° A