Consider
d'u
dr²+u = f(x)
subject to
subject to
u(0) = 0, u(x/2) = 0.
(14)
The goal in (a) is to find an integral representation for the unknown u(r) of the
form
u(x) = ™² G(E,x)ƒ (E)d£
(15)
where G(r, ) is the Green's function. Note that (15) only holds for homogeneous
boundary conditions (e.g. (14)).
(a) Solve for G(§, z) directly from
JG (§, x)
მ2
(13)
+G(§, x) = 8(§ - x)
(16)
G(0,r)=0
G(T/2, x) = 0.
(17)
You will need to determine and apply the matching conditions at = r as
discussed in lecture to find G(z, E) (see also Haberman page 388).
Fig: 1