Ciphertext space = Key space= (Z26)³. If the ciphertext is (11, 24, 5, 19, 22) and the key is (2, 20, 2.
10, 23), what is the decrypted plaintext? (5 points) ()
A. (13, 18, 7, 3, 19).
B. (9, 4, 7, 29, 25).
C. (13, 18, 3, 29, 25)
D. (9, 4, 3, 9, 25).
Fig: 1