4. What are the strength and direction of an electric f

Question

4. What are the strength and direction of an electric field that will balance the weight of a 1 g plastic sphere that
has been charged to -3 nC?

Nand Kishor Dambiwal · Accepted Answer

Accessibility: Investigate
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Ans 4:
To determine the strength and direction of an electric field that will balance the weight of
the charged plastic sphere, we need to consider the forces acting on the sphere.
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1. Weight (downward force): The weight of the sphere can be calculated using the equation
W = m* g, where W is the weight, m is the mass, and g is the acceleration due to gravity.
Since the mass is given as 1 g (0.001 kg) and the acceleration due to gravity is approximately
9.8 m/s², the weight W is 0.001 kg * 9.8 m/s² = 0.0098 N.
2. Electric force (upward force): The electric force acting on the charged sphere can be
calculated using the equation F = q* E, where F is the force, q is the charge, and E is the
electric field strength.
To balance the weight, the electric force should be equal in magnitude and opposite in
direction to the weight. Therefore, we can set F = -W = -0.0098 N.
q*E=-W
E=-W/q
Since the charge q is given as -3 nC (or -3 x 10^(-9) C), we can rearrange the equation to
solve for the electric field strength E:
E = -0.0098 N/(-3 x 10^(-9) C)
E = 3.27 x 10^6 N/C
Styles
The magnitude of the electric field required to balance the weight of the charged plastic
sphere is approximately 3.27 x 10^6 N/C. The direction of the electric field is upward,
opposing the downward force of gravity.
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