(50 pts; 2 pages) Material balance without reaction. Below is a simplification of a purification process for antibiotics produced by fermentation. Consider an aqueous stream containing an antibiotic (A) and

a contaminant (C) (Stream 1 on below process flow diagram). The antibiotic is purified by first extracting out into an oil that is immiscible with water; the contaminant is also extracted into this oil. Then, a reverse extraction occurs where water at a higher pH selectively extracts out the deprotonated form of the antibiotic.The distribution coefficient for the antibiotic in this reverse extraction is mass fraction A im oil phase – 0.2. The aqueous stream 5 leaving the reverse extraction unit mass fraction A in water contains 95% of the antibiotic freshly fed into the overall process (stream 1), and the purity of this antibiotic relative to the contaminant is 99% on a mass basis (e.g. water is not included in this calculation). (32 pts) Solve for the mass amounts of antibiotic and contaminant leaving the system Determine the mass fraction of antibiotic in stream 5. Determine the mass flow rate of oil (mg) needed to recirculate in the system.D/hr):