Question

7.23. Let CP denote carcinogenic potential, TR test results, and FR field

results. Suppose that for Figure 7.23 we have the following probabilities:

P(CP High) -0.27

P(TR Positive | CP High) = 0.82

P(TR Negative | CP High) = 0.18

P(FR Positive | CP High) = 0.95

P(FR Negative | CP High) = 0.05

P(CP Low) = 0.73

P(TR Positive CP Low) = 0.21

P(TR Negative | CP Low) = 0.79

P(FR Positive | CP Low) = 0.17

P(FR Negative | CP Low) = 0.83

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