A basketball player jumps straight up for a ball. To do this, he lowers his body 0.315 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.875 m above the floor. For this problem, use a coordinate system where up is positive.

Part (a) Calculate his velocity when he leaves the floor in m/s.

Part (b) Calculate his acceleration, in m/s2, while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.315 m.

Part (c) Calculate the magnitude of the force he exerts on the floor to do this, in

newtons, given that his mass is 108 kg.