Question . A heart defibrillator is used to resuscitate an accident victim by discharging a capacitor through the trunk of her body. The most simple defibrillator is an RC circuit. [8 points ] a. The 8.00-μF capacitor of the defibrillator is charged up to 1.00× 10³ V before use. What is the time constant of the circuit if her body provides a resistance of 1.00 × 10³ Q along the path the current travels? [ b. Calculate how long (in time) does it take the capacitor voltage to drop to only 5.00×10² V once it is used.(Hint: how is the voltage of and charge on the capacitor related?) [ 5 pts ]