Question

a. Mass of hydrate:-[(Mass of micro-crucible + hydrate)- (Mass of empty micro-crucible)] b. Mass of anhydrate:={(Mass of micro-crucible +anhydrate) - (Mass of empty micro-crucible)} c. Mass of water:u=[(Mass of hydrate)-

(Mass of anhydrate) d. Percentage of water in the hydrate (%) \frac{\text { Mass of water }}{\text { Mass of hydrate }} \times 100 e. Moles of anhydrate : Mass of anhydrate(g)* 1mol/ molar mass of anhydrate

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