Calculate AH for the reaction P4010(s) + 6PC15(g) → 10C3PO(g) given, ΔΗ = P4(s) + 6Cl2(g) → 4PC13(g) P4(s) + 502(g) → P4010(s) PC13(g) + Cl2(g) → PCI 5 (g) PC13(g)

+ (1/2)02(g) → Cl3PO(g) kj ΔΗ = -1225.6 kJ ΔΗ = −2967.3 kJ ΔΗ = −84.2 kJ AH = -285.7 kJ