Question

COMMENT A considerable savings in effort to force the fluid

through the pipe could be realized (0.179 kPa rather than 1.076 kPa)

if the flow could be maintained as laminar flow at this Reynolds

number. In general this is very difficult to do, although laminar

flow in pipes has been maintained up to Re 100,000 in rare

instances.

An alternate method to determine the friction factor for the For our case this gives

turbulent flow would be to use the Colebrook formula, Eq. 8.35a.

Thus,

1

VI

or

e/D

2.51

8 (37 +265/3) = -20 10g (030775

log

Rev

-2.0 log

-2.0 log 1.01 X 10+

0 log (1.0)

2.51

1.37 x 10 √f

1.83 x 10-4

By using a root-finding technique on a computer or calculator,

the solution to Eq. 1 is determined to be f = 0.0291, in agree-

ment (within the accuracy of reading the graph) with the Moody

chart method of f= 0.028.

Equation 8.35b provides an alternate form to the Colebrook

formula that can be used to solve for the friction factor directly.

Losses due to pipe

system components

are given in terms.

of loss coefficients.

-1.8 log (117)+--1.8 log[(0000375) +

-0.0289

This agrees with the Colebrook formula and Moody chart values

obtained above.

f-0.316(13,700)-25= 0.0292

which is in agreement with the previous results. Note that the

value of fis relatively insensitive to e/D for this particular situa-

tion. Whether the tube was smooth glass (e/D= 0) or the drawn

tubing (e/D= 0.000375) would not make much difference in

the pressure drop. For this flow, an increase in relative roughness

by a factor of 30 to e/D= 0.0113 (equivalent to a commercial

steel surface; see Table 8.1) would give f= 0.043. This would

represent an increase in pressure drop and head loss by a factor

of 0.043/0.0291 1.48 compared with that for the original

drawn tubing.

(1)

6.9

1.37 x 10¹

Numerous other empirical formulas can be found in the litera-

ture (Ref. 5) for portions of the Moody chart. For example, an

8.4 Dimensional Analysis of Pipe Flow

often-used equation, commonly referred to as the Blasius for-

mula, for turbulent flow in smooth pipes (e/D=0) with

Re< 10' is

f-

K₁ =

433

0.316

Rel/4

The pressure drop of 1.076 kPa in a length of 0.1 m of pipe

corresponds to a change in absolute pressure [assuming p=

101 kPa (abs) at x = 0] of approximately 1.076/101= 0.0107,

or about 1%. Thus, the incompressible flow assumption on which

the above calculations (and all of the formulas in this chapter) are

based is reasonable. However, if the pipe were 2 m long the pres-

sure drop would be 21.5 kPa, approximately 20% of the original

pressure. In this case the density would not be approximately

constant along the pipe, and a compressible flow analysis would

be needed. Such considerations are discussed in Chapter 11.

8.4.2 Minor Losses

As discussed in the previous section, the head loss in long, straight sections of pipe, the major losses,

can be calculated by use of the friction factor obtained from either the Moody chart or the Colebrook

equation. Most pipe systems, however, consist of considerably more than straight pipes. These addi-

tional components (valves, bends, tees, and the like) add to the overall head loss of the system. Such

losses are generally termed minor losses, with the corresponding head loss denoted h minor In this

section we indicate how to determine the various minor losses that commonly occur in pipe systems.

The head loss associated with flow through a valve is a common minor loss. The purpose of

a valve is to provide a means to regulate the flowrate. This is accomplished by changing the geom-

etry of the system (i.e., closing or opening the valve alters the flow pattern through the valve), which

in turn alters the losses associated with the flow through the valve. The flow resistance or head loss

through the valve may be a significant portion of the resistance in the system. In fact, with the valve

closed, the resistance to the flow is infinite-the fluid cannot flow. Such minor losses may be very

important indeed. With the valve wide open the extra resistance due to the presence of the valve

may or may not be negligible.

hy minor

(V²/28)

The flow pattern through a typical component such as a valve is shown in Fig. 8.21. It is not.

difficult to realize that a theoretical analysis to predict the details of such flows to obtain the head

loss for these components is not, as yet, possible. Thus, the head loss information for essentially all

components is given in dimensionless form and based on experimental data. The most common

method used to determine these head losses or pressure drops is to specify the loss coefficient, K₁,

which is defined as

Ap

p

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