0 & 0 \end{array}\right] \text { (b) } A=\left[\begin{array}{lll} 1 & 3 & 5 \\ 2 & 4 & 6 \end{array}\right] \quad B=\left[\begin{array}{l} -2 \\ 3 \\ 12 \end{array}\right] Show that A*B is not the same as B*A.
Fig: 1
Fig: 2
Fig: 3
Fig: 4