Consider the reaction between 5.00 gram of HCl and 28.0 g of lead nitrate according to the equation below,

HCl(aq) + Pb(NO3)2(aq) →>> HNO3(aq) + PbCl₂(s)

la) What is the maximum grams of precipitate that can be produced?

1b) What is the limiting reactant?

1c) How many grams of the excess reactant are left at the end of the reaction?

1d) If the reaction yield of a repeated trial was 75.6%, what was the actual experimental yield of precipitate in

grams?