For the circuit shown below, assuming zero charge on the capacitor at t= 0, the current flowing may be quantified as... i=\frac{E}{R} e^{\frac{-1}{R C}} Integrate this equation with respect to

t and hence find the charge stored in the capacitor one second after the switch is closed. The current (i) through a 10 mH inductor (L) has a relationship with time (t)as follows; i_{L}=\frac{1}{L} \int \cos (100 t) d t Determine the inductor current when the time is 0.9 seconds.