Given: \frac{\sin 3 \theta}{1+2 \cos \theta}=\sin \theta 1 Prove the above identity Why is the identity not valid for 0 = 60° \text { Solve the following equations } x \text { if } 0^{\circ}<x<90^{\circ} \text {; } 2 \tan x=-0.6842 \sin 2 x \cos x-\sin x \cos 2 x=0.500 \text { Show that } 15^{n}=\frac{\sqrt{3}-1}{2 \sqrt{2}} \text { Ghow that } \frac{\cos 330^{\circ} \tan 150^{\circ} \sin 12^{\circ}}{\tan 315 \cos \left(-258^{\circ}\right)}=\frac{1}{2}

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