Given: \text { Fluid 1: specific weight }=62.4 \mathrm{lb} / \mathrm{ft}^{3} \text { Fluid 2: density }=1.60 \text { slugs } / \mathrm{ft}^{3} \text { Fluid 3: specific gravity }=\text

{ ? } Find: The specific gravity of Fluid 3. Use Ywater=62.4 Ib/ft3