In Young's double slit interference experiment, we assume that the distance between two identical slits is a=0.5 mm and the distance between the slits and observation screen is L=10m.If the

wavelength of the incident light is 1 =500 nm and spectral width of the wavelength is 0.1 nm, please calculate followings: The vertical location of the third minimum. (b)The first location where the intensity of the light is half of the maximum. What will be happened if the width of one of the slits is doubled? (d)What is the maximum allowed optical path difference between the beams from two slits.