model i 8 thus given arst with a point u inside such that less than rs
Given ARST with a point U inside such that <RST = LRTS-42°. and ZRSU - LSRU-18°. Find
Let Af be the midpoint of BC. AM intersects CP at Q. By the symmetry properties. we may have
QBC (QCB = (PCB 3.
LPBQ = LPBCQBC 35"- 30" - 5".
namely, BP bisects ADQ. Morover, since
(ADP ABC-PBC (180-(BAC)- <PBC 25.
<AQP <<MQC = <MQB = 90° - 4QCM = 90 -<PCB Gr.
<PQD = 2<BCQ = 2(DCP = 60°.
<AQP = LPQB.
namely, QP bisects <AQB. To sum up. Pis the incenter of AABQ. Thus. Ar bisects BAQ. It
<BAP: <BAM =<BAC 25".
*The amount will be in form of wallet points that you can redeem to pay upto 10% of the price for any assignment. **Use of solution provided by us for unfair practice like cheating will result in action from our end which may include permanent termination of the defaulter’s account.Disclaimer:The website contains certain images which are not owned by the company/ website. Such images are used for indicative purposes only and is a third-party content. All credits go to its rightful owner including its copyright owner. It is also clarified that the use of any photograph on the website including the use of any photograph of any educational institute/ university is not intended to suggest any association, relationship, or sponsorship whatsoever between the company and the said educational institute/ university. Any such use is for representative purposes only and all intellectual property rights belong to the respective owners.