Question

Name: Michacia Lawrence T1S1 Solving Triangles Solve each triangle from the given measurements. Round your answer to the nearest tenth. 180 Sin 2) Cus COS(33.8 1) 67 9² = 36² 318336-318 √² = √733099828314 =30.9 132 181114=5/10 Sin (67) Sinton a=12.10 15 ft 9 670 B 65° (sin (67)=sin(1053) 15 15 15 36 yd 53.8° Z 31.8 yd 48 Sin (67/x = 13.59mLX = 5.6.1 SINT) MLA = a = 12.10 saमाज) X= 14.8 mLZ = 4014 C = 14.8 y = 3) A=Cus 228.64 880 COS 252-222-20 Q -2.22-26 22 in 25.6 in 20 in 4) Sin 48² = b² +45 2.6.45 48 ft M 71.7° 45 ft N mLP = 44.94 62°9 mLL = mLQ = 4994 mLN = 4574 mLR = 5614 n = 36ft Printable Math Worksheets @ www.mathworksheets4kids.com 11+ sin(60) = x 5.tan (50.1 x -95 are - Infinite Algebra 2 angle Tr asure of ea Name : Teacher: Name Michacia Lawrence . h 1 Score: Date: 12 e 3 25000 0567 NOT FOR INDIVIDU e 4.- Volume of Prisms, Pyramids, Cylinders, and Cones Find the volume of each figure. Round answers to the nearest hundredth, if necessary. Find the surface area of each figure. Show all work for full credit. 1) Piramid L.w.h 11.4.4 2) 4 mm 4mm Cylinder 8.6.8 3) 8 ft 6 ft 6 ft L.wh Volume: 384ft Volume: Surface Area 148825 85667 Volume: B Surface Area 11 mm 176mm 208mm Surface Area 288ft 2 (L⋅w+w•b) 2/4.11 +11+4 +4 11 W 2(L+w+w.h+h.) 4) Low⋅h v 4.11.87 LWW 28.6=48 6 Area 6 180(n-2) 5) then 10 180 (6-26) (4) ce Period 1 4 yd e Volume: Surface Area 11 yd /8 yd 352yd SA=2B+Ph SA=211) + 34/11) a 7) 22+374 22 3 yd Volume: Surface Area 3464 1-34 2016 22 574 8) = 5. 10 yd tan 6 cm 15 v=bhl (p.1) + (2+ baxaca) = X Volume: 2(12)+2(42) Surface Area 9) 12 cm 7 cm 2·2-4-2-8 V=8 65 4 in mm Volume: Surface Area 6 cm 12 cm 2244cm³ 2 in 2 in 8in '3 Volume: 2 mm 2 mm 8mm 3 Volume: 820cm Surface Area 31.32in Surface Area 24mm2 J

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