(4) P= 1²³R and V=IR Nominal Resistance = 301 and power Rating = 500W 500 = I²R = 1=500 30 = 4.08 A V= IR = 122.47 V Puncertainty in R÷

=) error accuraly = 0.5%, resolution = 1 V 30x0.5 = PEP. 1 => error = 0.5%, uncertainty in I = accuracy = 0,1%, resolution = 100mA Range => error will be according to 1A= error = 0.1 X 10 = 1% ... uncertainty in V = 1% +0,5% = 1.5%. ... Range = 122.47±1.5% = 122.47 ± 1.832 = 120.64 to 124.30 124 300