Part 2: Crack Propagation A long, thin steel plate, width W-100mm and thickness t = 3mm, has a single edge crack of length a=2mm. The plate is subjected to tension-tension cyclic

loading between constant values of minimum and maximum stress, σmin = 40MPa and max 160Mpa. The crack configuration factor is given by: y² = 1.25 1.516.5 [1-0.7 (w)"]** The material Paris Law constants for stress ratio R CR=0 5.30x10-13 = m R=0 = = 3.25 m/cycle (MPa √m)" m a W = 0 are: The Walker equation parameter y for the material is: y = 0.4 y = 0.0 R≥O R<0 σ Using Walker equation mean stress correction, calculate the number of load cycles required for the crack to grow to length a=10mm: a) Assuming Y is constant at the initial crack length value throughout. Show the full working in your submission. [10 marks] b) A 3 stage solution with updated Y. If you do this part using a computer program, state the software used, describe the analysis procedure, and submit a copy of your program (input) file. [6 Marks] c) Numerical Integration using software of your choice. State the software used, describe the analysis procedure, including how the required integral was obtained, and submit a copy of your program (input) file. [10 marks]