Problem 1
The beam shown below is subjected to only two types of loads: live load w.= 0.7 k/ft, and dead load wp=
1.5 k/ft. Based on the ASCE 7-16 basic load combinations, determine the following:
(1) maximum factored negative moment Mu at support B
(2) maximum factored negative moment Mu at support D
(3) maximum factored positive moment M. at section E (mid-span of DF)
(4) maximum factored shear V. at the immediately right side of section D
F
TRB
Load combination
At C
B
16 ft
4 MB =
T
32 ft
с
RD = 327.04 K
RD
= 146 k
+
16 ft
1.2 №
+ 1.6 WL
= 1.2 (1.5) + 1.6 (0.7)
PB + RD +RF = 2.92 (1125+) = 327.04 k.
19
=) RB (32) = 3363.84
B = 105.12 K
FRD
+ +
16 ft
2.92 (48) (24) R8 (32)
16 ft
= 75.92 K
-
Moment at D: 2.92 (64) (32) - RB (48) = (2.92 x 48×24) - RF (32)
=) RF
F
105. 12k 75.92k
- 2.92 (16) (8) = √-373.76 k-ft
16 ft
= 2.92 k/ft
-2
MD = 75.92 (16)- 2.92 (48) (24)
37 Maximum positive My at E =0 because there in
(2149.126-11)
no positive
moment at DF
estion with Student's solution | Need to match with Professor's solution | Handwritten solution is needed/nVD =
V0 =
VD= 64.24 kips
2.92 (48)
RF
2-92 (48) -75.92/nops.tutorbin.com/assignment X
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For the HW1,
Please consider the following two fundamental load
combinations (same in ASCE 7-16 and ASCE 7-22):
(1) 1.4D
(2) 1,2D + 1.6L
The following shows the answers of the first
problem:
Mu for negative moment at B: 373.8 k-ft
Mu for negative moment at D: 1006 k-ft
Mu for positive moment at E: 6.4 k-ft
Vu for shear at right side of D: 70.96 kips
Professor's answer
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