Q.2 (50 pts.) A cubical furnace has wall dimensions of 4 meters. Top and side surfaces are black and

maintained at temperatures 900 K and 1500 K, respectively. Bottom surface has an emissivity of 0.6

and maintained at 500 K. Fill in the results in the table. Also upload your hand solutions.

Hint: The radiosity of the side and top surfaces are equal to their emissive power, i.e. J-Es=oT¹, as

they are black. So you can use the following equation to determine the radiosity of the bottom surface:

Ebi-J₁ J₂-J₁, J₁ J₁

+

R12 R₁3

R₁

+

=0

T₂=900 K

6₂=1

T3 = 1500 K

€3 = 1

T₁ = 500 K

€₁=0.6