Question

Q2) The dissociation energy (from the zero-point vibrational level) of the ground state N2 (1g + )molecule is 7.2 eV. There exists an electronically excited 3 epsilon state of N,

whose zero-point levellies at 5.1 eV above the zero-point level of the ground state. Both of these states dissociate to the two ground state atoms N (4S). In addition, there is a 3IIg state of N2 that has a zero-point energy 6.2 eV above the ground state, which dissociates into a ground state N (*S) and an excited state N* (²D), which lies 2.4 eV above ground state N. a) Sketch the potential energy curves for the three N2 states described.. Make sure you show at least relative energies. On your sketch, draw an excitation path from ground state N, to two free Ns ( 4S). \text { Calculate the dissociation energy of } \mathrm{N}_{2} \text { into } \mathrm{N}\left({ }^{4} S\right) \text { and } \mathrm{N}^{*}\left({ }^{2} \mathrm{D}\right) \text {. }

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