Suppose f(x)=\left(\frac{1}{27}\right)^{-3 x+3} Solve for a in the following equation f (x) = 9 \mathbf{A}\left[x=\left(\frac{11}{8}\right)\right] \mathbf{B}\left[x=\left(\frac{11}{9}\right)\right] \begin{array}{|c|} \hline & \left.x=\left(-\frac{30}{49}\right)\right] \end{array} \text { D }\left[x=\left(\frac{5}{28}\right)\right] \text { E }\left[x=\left(-\frac{7}{6}\right)\right] \text

{ F none of these }