following mechanism:
Write the balanced
chemical equation for the
overall chemical reaction:
step
rate constant
elementary reaction
NO(g) + Br₂(9) NOBr₂(9)
1
k₁
2
NOBr₂(g) + NO(g) → 2 NOBr(g)
k₂
Suppose also k₁«k₂. That is, the first step is much slower than the second.
Write the experimentally-
observable rate law for the
overall chemical reaction.
Note: your answer should
not contain the
concentrations of any
intermediates.
Express the rate constant
k for the overall chemical
reaction in terms of k₁, K₂,
and (if necessary) the rate
constants k.1 and K-2 for
the reverse of the two
elementary reactions in
the mechanism.
0
rate=&
10
-
-0
ローロ
olo
11
8
X
G
Ar
12
Fig: 1