What is the voltage conversion ratio Va/V1 for this converter assuming periodic steady-state continuous conduction mode operation? [Select the one best answer from the choices given below] \text { (a)

} \frac{V_{2}}{V_{1}}=\frac{N_{1}}{N,} \frac{D}{1-D} \text { (b) } \frac{V_{2}}{V_{1}}=\frac{N_{1}}{N_{2}} \frac{1}{1-D} \text { (c) } \frac{V_{2}}{V_{1}}=\frac{N_{1}}{N_{2}} D \text { (d) } \frac{V_{2}}{V_{1}}=\frac{N_{2}}{N_{1}} \frac{D}{1-D} \text { (e) } \frac{V_{2}}{V_{1}}=\frac{N_{2}}{N_{1}} \frac{1}{1-D} \text { (f) } \frac{V_{2}}{V_{1}}=\frac{N_{2}}{N_{1}} D ^^20(g)^^20\frac{V_{2}}{V_{1}}=-\frac{N_{1}}{N_{2}}\frac{D}{1-D} \text { (h) } \frac{V_{2}}{V_{1}}=-\frac{N_{1}}{N_{2}} \frac{1}{1-D} ^^20(j)^^20\frac{V_{2}}{V_{1}}=-\frac{N_{2}}{N_{1}}\frac{D}{1-D} \text { (k) } \frac{V_{2}}{V_{1}}=-\frac{N_{2}}{N_{1}} \frac{1}{1-D} ^^20(i)^^20\frac{V_{3}}{V_{1}}=-\frac{N_{2}}{N_{1}}D