The magnitude and coordinate direction angles of three vectors are given below Determine the magnitude and the coordinate direction angles of the sum of the three vectors Vector A magnitude:

266 N \begin{array}{l}\text{^^20}\alpha\text{:^^20}38^2 \\ \beta\colon94^2 \\ \text{^^20}\gamma\colon\text{^^20}52^{\prime}\end{array} \begin{array}{l}a\colon83^{\circ} \\ \beta\colon26^{\circ} \\ y\colon\text{^^20}65^{\circ}\end{array} Vector B Vector C magnitude 193 N magnitude: 149 N \begin{aligned} & a)\text{^^20Magnitude:^^20188}\mathrm{N};\text{^^20}\alpha\colon\text{^^20}37^{\circ};\beta\colon49^{\circ};\gamma\colon41\text{^^20}^{\circ} \\ & b)\text{^^20Magnitude:^^20402}\mathrm{N};\alpha\colon81^{\circ};\beta\colon52^{\circ};\gamma\colon40^{\circ} \\ & c)\text{^^20Magnitude:^^20213}\mathrm{N};\alpha\colon64^{\circ};\beta\colon85^{\circ};\gamma\colon29^{\circ} \\ & d)\text{^^20Magnitude:^^20402}\mathrm{N};\text{^^20}\alpha\colon\text{^^209}^{\circ};\beta\colon38^{\circ};\gamma\colon50^{\circ} \\ & e)\text{^^20Magnitude:^^20608}\mathrm{N};\alpha\colon40^{\circ};\beta\colon73^{\circ};\gamma\colon31^{\circ}\end{aligned} \begin{array}{l}\text{^^20}\alpha\text{:^^20}146^{\circ} \\ \text{^^20}\beta\colon\text{^^20}81^{\circ} \\ \text{^^20y:}58^{\circ}\end{array}