Question

The standard enthalpy change for the following reaction is -1.63×10 kJ at 298 K. Ca(s) + Si(s) + 3/2 0,(g)CaSiO3(s)AH° = -1.63×103 kJ What is the standard enthalpy change for

the reaction at 298 K? 2 CaSiO3(s) – 2 Ca(s) + 2 Si(s) +3 02(g)

Fig: 1

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