Watch the video and see how data is typically collected. Write down the values presented in the video. The first column is volts (volts) and the second column is current

(Amps). Note that the current will be presented in mill-amps. Convert that to amps. The spreadsheet is provided but going through the video and studying how the circuit is constructed is always a bonus. 1. Plot current vs. voltage. Label the graph. Is it linear? 2. Perform a LINEST. Note: The slope should be . Note the slope and the uncertainty. Compare with the measured value (multimeter) of R. [R =97.8 +0.1 N] 3. Answer the following: a. From your results, did your conductor (resistor component) obey Ohm's Law? b. Did you compare reasonably with the actual value of R? b. Explain the proper conditions for utilizing am ammeter in this experiment. What properties does it have and how was it placed in the circuit? He llo. >> What we have here is just a simple series circuit with a single resistor over here. >> And our blue box, what we have is a function generator,but it's going to be set at dc so that the votes that we put in there are not going to be changing with time at all and change when we change the value our selves. And here we have a simple circuit board that you should be familiar with by now, and a key plea to measure current. So what happens here is we have output from our voltage source into the input of our ammeter. >> And then this cable here is out of the m meter into the board, going to jump over and put power into the board. >> And then we have current flowing back again through the voltage source. So it's just a sing le loop with a single resistor. Ok, so now what we're going to do is see if our resistor will act as a conductor which obeys Ohm's Law. So you will be given a voltage and we're going to read the current at that particular voltage, plot, the current versus voltage or an IV curve and see if it's truly linear. Okay, so let's go ahead and begin now. >>Notice where the digit is. The digit is right here. >> And then also notice that we have, we're reading the current in milliamps. >> So the values that you read here will be ten to the minus three amps. >> And when you do your plot, you have to make sure that the current is in amps, not milli amps. >> So you'll have to convert, say, reading, let's put it to 0.4 volts and read the current note, the decimal here, and read it to three significant digits. >> Okay, now we're going to change the vaults to 1. >> so at 1 volts, read the current to three significant digits. >> Note your rules for rounding in such. >> ok. Let's change it to 1.3 volts and read the current to three significant digits. >> And note,we're in milli amps, right? We're going to take it to 1.7 volts, read the current and the 2 votes, and now to 2.5 volts and finally to 3.2 volts. >> Ok,so now what we're gonna do is we're going to take the voltage back down to 0 and we're going to insert another component into our circuit. This is a simple LED.>> It's just a light emitting diode, but it has to be activated. > In other words, is even though that we may have apply power to the circuit, doesn't necessarily mean that it will start activation immediately. Now if I put that in the board correct ly, we should see activation at a particular voltage depending on the wave length. Here we're looking at red, so that part of the visible spectrum. >> Okay, notice that when we increase the voltage up to about 1.71.8,we notice that the diode became activated. » So for this particular wave length,we measure an activation voltage of about 1.7. Notice the current that we have through this particular diode at that voltage. And we need to have a resistor.If we're gonna use DC, we need to have a resistor in series so that we don't shock it or are put through too much current through it as it'll, it'll blow.These particular diodes are very sensitive to that. >> So if I were putting in green, you would measure a different activation voltage versus blue and yellow.>> Okay, see you soon.