Question

) Which of the following is the correct integral to find the volume by cylindrical shell method 2 \pi \int_{0}^{1}\left(6 x^{10}\right) d x 2=\int_{0}^{6}\left(x^{10}\right) d x \frac{2 \pi}{6} \int_{0}^{6}\left(y^{10 /

9}\right) d y 2 \pi \int_{0}^{6} y\left(\frac{y}{6}\right)^{1 / 9} d y 2 \pi \int_{0}^{6} y\left(6 y^{9}\right) d y () Which of the following is the correct integral to find he volume by disk method \int_{0}^{1}\left(6^{2}-0^{2} z^{29}\right) d x =\int_{0}^{1} y^{2}\left(d^{2} y^{29}\right) d y 0=\int_{0}^{1} y^{2}\left(\frac{y^{2}}{6^{2}}-\left(\frac{y}{6}\right)^{2 / 9}\right) d y \pi \int_{0}^{1}\left(\begin{array}{l} x \\ 6 \end{array}\right)^{2 / 0} d x x \int_{0}^{6}\left(\frac{y}{6}\right)^{2 / 9} d y

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