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  • Q1:Instructions Part A: You will find an excel sheet attached. Ch1 homework data set.xlsx A survey asked three questions to pet owners: 1. How many pets do you own? 2. Do you like cats, dog, or neither cats nor dogs the best? 3. How much time in hours does your pet(s) stay home on average per day? Create an appropriate graph for each question using Minitab. Identify what type of data is obtained from each question (qualitative, quantitative discrete, or quantitative continuous). Use one pie chart, one bar graph and one histogram. Copy the graphs to a word file and indicate which type of data near the graph. You can copy graphs from Minitab and then paste them into a word document and then you will be able to write in the type of data that each is. Note: Histograms are good for continuous data because the bars do not have spaces between them, and continuous data does not have jumps between numbers. Part B:See Answer
  • Q2:Part B: Visit the Infographics Site for Statistics Canada at https://www150.statcan.gc.ca/n1/pub/11-627-m/index-eng.htm Find a poster (scroll down) that is on a topic that interests you and that contains a pie graph. Be sure you can answer the questions below by looking at your pie graph. 1. Copy the pie graph from the poster and add it to your word document. 2. Pie graphs usually show percentages and should add up to 100%. Does your pie graph add to 100%? If it doesn't, why not? 3. What would have been the question that was asked to gather the data displayed on your pie graph? Remember that the question is usually qualitative. Your written response should be submitted as a pdf file.See Answer
  • Q3:1. DETAILS DEVORESTAT9 8.3.035.S. MY NOTES The article "Uncertainty Estimation in Railway Track Life-Cycle Cost"+ presented the following data on time to repair (min) a rail break in the high rail on a curved track of a certain railway line. 159 120 480 149 270 547 340 43 228 202 240 218 A normal probability plot of the data shows a reasonably linear pattern, so it is plausible that the population distribution of repair time is at least approximately normal. The sample mean and standard deviation are 249.7 and 145.1, respectively. (a) Is there compelling evidence for concluding that true average repair time exceeds 200 min? Carry out a test of hypotheses using a significance level of 0.05. State the appropriate hypotheses. ⒸM-200 H₁: <200 ⒸM-200 H₂>200 No 200 H₂-200 ⒸM-200 H: 200 ⒸM₂: > 200 MH-200 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) t= P-value= What can you conclude? There is compelling evidence that the true average repair time exceeds 200 min. There is not compelling evidence that the true average repair time exceeds 200 min. (b) Using a 150, what is the type II error probability of the test used in (a) when true average repair time is actually 300 min? That is, what is (300)? (Round your answer to two decimal places. You will need to use the appropriate table in the Appendix of Tables to answer this question.) A(300) - MacBook ProSee Answer
  • Q4:2. DETAILS DEVORESTAT9 8.4.043.S. A common characterization of obese individuals is that their body mass index is at least 30 (BMI = weight/(height), where height is in meters and weight is in kilograms]. An article reported that in a sample of female workers, 269 had BMIs of less than 25, 158 had BMIs that were at least 25 but less than 30, and 121 had BMIS exceeding 30. Is there compelling evidence for concluding that more than 20% of the individuals in the sampled population are obese? (a) State the appropriate hypotheses with a significance level of 0.05. ⒸM₂: P = 0.20 HP 0.20 ⒸH₂¹ P >0.20 HP-0.20 H₂ P=0.20 H:p>0.20 ⒸN₂: P-0.20 H₂ p<0.20 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value- What can you conclude? Reject the null hypothesis. There is not sufficient evidence that more than 20% of the population of female workers is obese. Reject the null hypothesis. There is sufficient evidence that more than 20% of the population of female workers is obese. Do not reject the null hypothesis. There is sufficient evidence that more than 20% of the population of female workers is obese. Do not reject the null hypothesis. There is not sufficient evidence that more than 20% of the population of female workers is obese. (b) Explain in the context of this scenario what constitutes type 1 error. A type I error would be declaring that 20% or less of the population of female workers is obese, when in fact more than 20% are actually obese. A type I error would be declaring that 20% or more of the population of female workers is obese, when in fact less than 20% are actually obese. A type 1 error would be declaring that less than 20% of the population of female workers is obese, when in fact 20% or more are actually obese. A type I error would be declaring that more than 20% of the population of female workers is obese, when in fact 20% or less are actually obese. Explain in the context of this scenario what constitutes type 11 error. ( A type II error would be declaring that 20% or less of the population of female workers is obese, when in fact more than 20% are actually obese. A tune II er would be decladog that 300 or more of the population of female workers in ober fact leve than 2016 cu obs MY NOTES MacBook Pro/n3. H₂DU.EU ⒸHOP=0.20 H: P < 0.20 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value= What can you conclude? Reject the null hypothesis. There is not sufficient evidence that more than 20% of the population of female workers is obese. Reject the null hypothesis. There is sufficient evidence that more than 20% of the population of female workers is obese. Do not reject the null hypothesis. There is sufficient evidence that more than 20% of the population of female workers is obese. Do not reject the null hypothesis. There is not sufficient evidence that more than 20% of the population of female workers is obese. (b) Explain in the context of this scenario what constitutes type 1 error. A type 1 error would be declaring that 20% or less of the population of female workers is obese, when in fact more than 20% are actually obese. A type 1 error would be declaring that 20% or more of the population of female workers is obese, when in fact less than 20% are actually obese A type 1 error would be declaring that less than 20% of the population of female workers is obese, when in fact 20% or more are actually obese. A type 1 error would be declaring that more than 20% of the population of female workers is obese, when in fact 20% or less are actually obese. Explain in the context of this scenario what constitutes type II error. A type II error would be declaring that 20% or less of the population of female workers is obese, when in fact more than 20% are actually obese. A type 11 error would be declaring that 20% or more of the population of female workers is obese, when in fact less than 20% are actually obese. A type II error would be declaring that less than 20% of the population of female workers is obese, when in fact 20% or more are actually obese. A type II error would be declaring that more than 20% of the population of female workers is obese, when in fact 20% or less are actually obese. (c) What is the probability of not concluding that more than 20% of the population is obese when the actual percentage of obese individuals is 27%? (Round your answer to four decimal places.) You may need to use the appropriate table in the Appendix of Tables to answer this question. Submit Answer DETAILS DEVORESTAT9 9.1.005. MY NOTESSee Answer
  • Q5:3. Submit Answer DEVORESTAT9 9.1.005. DETAILS Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood qrculation in fingers and toes. In an experiment to study the extent of this impairment, each subject immersed a forefinger in water and the resulting heat output (cal/cm2/min) was measured. For m = 8 subjects with the syndrome, the average heat output was - 0.65, and for n=8 nonsufferers, the average output was 2.01. Let #, and , denote the true average heat outputs for the sufferers and nonsufferers, respectively. Assume that the two distributions of heat output are normal with o,-0.1 and %₂=0.3. (a) Consider testing H₁ H₁-H₂=-1.0 versus H: ₂-₂-1.0 at level 0.01. Describe in words what H, says, and then carry out the test. OH, says that the average heat output for sufferers is the same as that of non-sufferers. ⒸH, says that the average heat output for sufferers is less than 1 cal/cm³/min below that of non-sufferers. CH, says that the average heat output for sufferers is more than 1 cal/cm²/min below that of non-sufferers. Calculate the test statistic and P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) 2= P-value- State the conclusion in the problem context. Fail to reject H₂. The data suggests that the average heat output for sufferers is the same as that of non-sufferers. Reject Ho. The data suggests that the average heat output for sufferers is more than 1 cal/cm/min below that of non-sufferers. Fail to reject H. The data suggests that the average heat output for sufferers is less than 1 cal/cm2/min below that of non-sufferers. Reject Ho. The data suggests that the average heat output for sufferers is the same as that of non-sufferers. (b) What is the probability of a type II error when the actual difference between ₁ and ₂ is ₁-₂ -1.5? (Round your answer to four decimal places.) (c) Assuming that m-n, what sample sizes are required to ensure that = 0.1 when H₁-H₂=-1.5? (Round your answer up to the nearest whole number.) subjects You may need to use the appropriate table in the Appendix of Tables to answer this question. MY NOTES MacBook ProSee Answer
  • Q6:DETAILS DEVORESTAT9 9.2.028.5. As the population ages, there is increasing concern about accident-related injuries to the elderly. An article reported on an experiment in which the maximum lean angle-the farthest a subject is able to lean and still recover in one step-was determined for both a sample of younger females (21-29 years) and a sample of older females (67-81 years). The following observations are consistent with summary data given in the article: YF: 29, 35, 31, 27, 28, 32, 31, 34, 32, 29 OF: 19, 15, 21, 13, 12 Does the data suggest that true average maximum lean angle for older females (OF) is more than 10 degrees smaller than it is for younger females (YF)? State and test the relevant hypotheses at significance level 0.10. (Use , for younger females and #₂ for older females.) Hoi H₁ H₂O Mo 1-₂-10 H₂H₁-H₂> 10 ⒸH²H₁-H₂10 H₂H₁₂ <10 ⒸHM₁₂0 H₂H₂-H₂>0 P-value- Calculate the test statistic and determine the P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) tm MY NOTES State the conclusion in the problem context. Fall to reject M. The data suggests that true average lean angle for older females is more than 10 degrees smaller than that of younger females. Fail to reject Ho. The data suggests that true average lean angle for older females is not more than 10 degrees smaller than that of younger females. Reject Ho. The data suggests that true average lean angle for older females is not more than 10 degrees smaller than that of younger females. Reject Ho. The data suggests that true average lean angle for older females is more than 10 degrees smaller than that of younger females.See Answer
  • Q7:5. DETAILS DEVORESTAT9 9.3.040. Lactation promotes a temporary loss of bone mass to provide adequate amounts of calcium for milk production. A paper gave the following data on total body bone mineral content (TBBMC) (g) for a sample both during lactation (L) and in the postweaning period (P). Subject 2 3 5 6 7 L 1929 2546 2825 1923 1628 2175 2112 2621 1843 2542 1 4 8 9 10 P 2127 2885 2895 1943 1750 2183 2164 2626 2006 2626 (a) Does the data suggest that true average total body bone mineral content during postweaning exceeds that during lactation by more than 25 g? State and test the appropriate hypotheses using a significance level of 0.05. [Note: The appropriate normal probability plot shows some curvature but not enough to cast substantial doubt on a normality assumption.] (Use H₂Hp - H₂.) ⒸH₂= 25 H₂H ≤ 25 Hoo-25 H₂H25 ⒸH₂=25 H₂H > 25 H₂H25 H₂H <25 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) t= MY NOTES P-value- State the conclusion in the problem context. Fall to reject Ho. The data suggests that the true average total body bone mineral content during postweaning exceeds that during lactation by more than 25 g. Reject Ho. The data suggests that the true average total body bone mineral content during postweaning does not exceed that during lactation by more than 25 g. Reject Ho. The data suggests that the true average total body bone mineral content during postweaning exceeds that during lactation by more than 25 g. Fall to reject Ho. The data suggests that the true average total body bone mineral content during postweaning does not exceed that during lactation by more than 25 g./n6. HoHo 25 H₂HD > 25 ⒸHo Ho - 25 H:H₂ < 25 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) to P-value= State the conclusion in the problem context. ⒸFall to reject H₂. The data suggests that the true average total body bone mineral content during postweaning exceeds that during lactation by more than 25 g. Reject Ho. The data suggests that the true average total body bone mineral content during postweaning does not exceed that during lactation by more than 25 g. Reject Ho. The data suggests that the true average total body bone mineral content during postweaning exceeds that during lactation by more than 25 g. Fall to reject Ho. The data suggests that the true average total body bone mineral content during postweaning does not exceed that during lactation by more than 25 g. (b) Calculate an upper confidence bound using a 95% confidence level for the true average difference between TBBMC during postweaning and during lactation. (Round your answer to two decimal places.) 9 (c) Does the (incorrect) use of the two-sample t test to test the hypotheses suggested in (a) lead to the same conclusion that you obtained there? Explain. Yes, if the two samples were independent, the result would be the same. No, if the two samples were independent, the result would not be the same. You may need to use the appropriate table in the Appendix of Tables to answer this question. DETAILS Submit Answer DEVORESTAT9 9.5.064. The following observations are on time (h) for an AA 1.5-volt alkaline battery to reach a 0.8 voltage. Brand A: 8.65 R.84 R.91 8.82 875 8 52 872 878 876 MY NOTESSee Answer
  • Q8:6. DETAILS DEVORESTAT9 9.5.064. The following observations are on time (h) for an AA 1.5-volt alkaline battery to reach a 0.8 voltage. Brand A: 8.65 8.84 8.91 8.82 8.75 8.52 8.72 8.78 8.76 Brand B: 8.86 8.71 8.71 8.8 8.73 8.76 8.78 8.74 8.79 Normal probability plots support the assumption that the population distributions are normal. Does the data suggest that the variance of the Brand A population distribution differs from that of the Brand B population distribution? Test the relevant hypotheses using a significance level of 0.05. [Note: The two-sample t test for equality of population means gives a P-value of 0.733.] The Brand A batteries are much more expensive than the Brand B batteries. State the relevant hypotheses. (Use a, for Brand A batteries and a₂ for Brand B batteries.) ⒸH₂0₁ ¹0₂² ⒸH: 0²-0₂² M₂: 0,² > 0₂² H₁: 0 ₁ ² = 0₂² M₂:0₂ ² = 0₂² Calculate the test statistic. (Round your answer to two decimal places.) fm What can be said about the P-value for the test? ⒸP-value > 0.100 0.050 < P-value < 0.100 0.010 < P-value < 0.050 0.001 < P-value < 0.010 OP-value < 0.001 MY NOTES State the conclusion in the problem context. Reject H. The data suggests that there is difference in the population variances of the two battery brands./nⒸH₂:0₁ ²0₂ ² H₂: 0₂² 20₂² ⒸH₂:0₁²-0₂² Calculate the test statistic. (Round your answer to two decimal places.) f= What can be said about the P-value for the test? OP-value > 0.100 0.050 < P-value < 0.100 0.010 < P-value < 0.050 0.001 < P-value < 0.010 OP-value < 0.001 State the conclusion in the problem context. Reject Ho. The data suggests that there is difference in the population variances of the two battery brands. Fail to reject Ho. The data does not suggest that there is difference in the population variances of the two battery brands. Fail to reject Ho. The data suggests that there is difference in the population variances of the two battery brands. Reject Ho. The data does not suggest that there is difference in the population variances of the two battery brands. You may need to use the appropriate table in the Appendix of Tables to answer this question. Submit Answer Home My Assignments Request ExtensionSee Answer
  • Q9:Question 1 The editor of a UK college magazine is checking the latest edition of the magazine before it goes to print, but they have found some problems. (a) Three stories each have a piece of data missing. The topics of the three stories are: Story 1: A science project to find the fastest reaction time when mixing certain chemicals. Story 2: An interview with the winner of the inter-collegiate 1500 metre race. Story 3: The results of a survey to find the average time it took students to travel from their home to the entrance of the college campus. The three pieces of data are: A: 5 minutes 33 seconds B: 42 minutes C: 31.4567 seconds Match each story with the most appropriate piece of data, justifying your answer. (b) A story about the campus shop says that students spend on average £4.5682351 per visit. The editor rightfully thinks that this level of accuracy is unjustified. Round £4.5682351 to an appropriate level of accuracy, justifying your answer. (c) The word counts for the main articles in the latest magazine edition are: 220, 470, 1300, 250, 1100, 540, 380, 670. (i) Calculate by hand the median word count. Show your working. (ii) Calculate by hand the range of word counts. Show your working. See Answer
  • Q10:Question 2 A biologist is studying the development of a small population of rabbits. The length of each rabbit is recorded at the age of 3 weeks old and again at the age of 6 weeks old. The Minitab worksheet rabbits.mwx contains two columns. The column 3 weeks gives the length of each rabbit in millimetres at 3 weeks old and the column 6 weeks gives the corresponding length of the same rabbit in millimetres at 6 weeks old. Run Minitab and open this worksheet.See Answer
  • Q11:Question 3 The Office for National Statistics publishes the average price per litre in pence of ultra low sulphur/unleaded petrol (www.ons.gov.uk/economy/inflationandpriceindices/timeseries/czmk/mm23). The Minitab worksheet petrol.mwx contains the data for 2021 and has two columns. The column month gives the survey month where January is month 1. The column price2021 gives the average price in pence per litre in the year 2021.See Answer
  • Q12:Question 4 A group of 20 Open University students completed a practice quiz. The results for their first attempt were recorded and are represented in the following stemplot:See Answer
  • Q13:Question 5 A garden centre selling spring bulbs places a bulk order with their supplier each autumn for the following year's requirements of daffodil and tulip bulbs. The data for 2020 and 2021 are displayed in Table 1. (a) Calculate the overall spring bulb price ratio for 2021 relative to 2020. Round your answer to three decimal places. (b) Calculate the value of the spring bulb price index for 2021, taking 2020 as the base year. Round your answer to one decimal place.See Answer
  • Q14:Question 6 The Office for National Statistics publishes the Retail Price Index (RPI) and related data (www.ons.gov.uk/economy/inflationandpriceindices). Price ratios and weights from the year 2020 are listed in Table 2. (The base date was January 1987.) (a) Why are pensioner households and high-income households excluded from the RPI? Justify your answer. (b) By considering the price ratio for 'Food and catering' in Table 2, comment on whether the food and catering prices in November 2020 have increased or decreased relative to January 2020. Justify your answer. (You do not need to calculate the percentage change.) (c) Using the data given in Table 2 (i) Show that the unrounded all-item price ratio for November 2020 relative to January 2020 is 1.009953. (ii) The value of the RPI in January 2020 was 290.6. Using the all-item price ratio given above in part (i), find the value of the RPI in November 2020 rounded to one decimal place. (d) An RPI index-linked pension was £733 per month in January 2020. The value of the RPI in January 2021 was 294.6. How much should the pension be per month in January 2021? Please give your answer rounded to the nearest pound. (e) Using relevant values of the RPI, calculate the purchasing power of the pound in January 2021 compared with the base date January 1987. Please give your answer rounded to the nearest penny.See Answer

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