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Q1:1. (25 pts) A solar panel is mounted facing due south in a location at 40° N latitude, with a tilt angle of 38° (south facing). If the sun shines on the panel for the entire day on the spring equinox with clear skies, calculate the total energy incident per square meter on the panel during the course of the day in kWh/m². (Use the direct normal values shown in the table below). Hour 1 2 3 4 5 6 7 8 9 10 11 12 13 15 16 17 18 19 20 21 22 23 24 Normal Irradiance [w/m2] 0 0 0 0 0 130.00 480.00 756.00 875.00 892.00 908.00 915.00 908.00 892.00 875.00 756.00 480.00 130.00 0 0 0 0 0 0 2. (10 pts) A house at 48° N latitude has a roof that faces due south, and is elevated to an angle of 28°. A solar panel is mounted to the roof. What is the angle of incidence between the sun and the array. 1 p.m. on June 1?See Answer
Q2:Problem 1 (10 pts) Assume that coal has a sulfur content of 3% by weight. If all the sulfur is converted into SO2 during the combustion process, (a) how much SO₂ is produced per tonne of coal? (b) How much is produced per megajoule of energy produced? The molecular mass of sulfur is 32 gram mole. Sulfur content in 1 tonne of coal is given (or may be found from what's given); you need to find out the content of SO2 when I tonne of coal is burned. So, find out the ratio (of molar mass) of S in SO2; from here you can determine the SO₂ content./nProblem 2 (10 pts) A typical gasoline-powered vehicle requires about 3.7 MJ of primary energy (i.e., energy content of the gasoline) to travel 1 km. How many kilograms of CO2 are produced annually by a vehicle that is driven 40,000 km per year? From the energy content of gasoline (octane), you may find out the amount (kg) of gasoline required to drive the vehicle annually. The chemical reaction for burning octane is given by: 2C8H18 + 250216CO2 + 18H20 From here, you can find out how many grams of octane yields what amount of CO2, which may then be used to find the total CO2 produced.See Answer
Q3:Consider the purchase of a 4-watt LED light to replace a 35-watt incandescent light. The LED light costs $3 and is estimated to save $0.48 per year in electricity costs if replacing the 35-watt incandescent light. The new light has an estimated lifetime of 12 years. Assume a discount rate of 6% and electricity costs $0.13/kWh. What is the levelized cost of saved energy, in $/kWh. That is, how much has to be paid per kWh of electricity saved? Be careful about the sign (Explain your answer in words, for clarity.)See Answer
Q4:Course work: Design a heat pump to heat the James Watt Building South This course work assignment is part of the final assessment of this course, and it accounts for 25 marks (25% of the total assessment). Objective: The peak heating demand of the James Watt Building South is assumed to be 400 kW. Its heating network system delivers heat by pumping hot water at 80 *C through radiators. The measured river water temperature for most of the heating season is in the range 6-10 °C. After extracting heat, the cold water should be returned to the river with a temperature no less than 4 °C. You are expected to apply the learned thermodynamics knowledge and skills to conduct a conceptual design of a two-stage water source heat pump to extract heat from the water of river Kelvin to heat the James Watt Building South.See Answer
Q5:1 The temperatures of the hot and cold reservoirs are: = 1050°F = 565°C = 839 K T=554°F = 295°C = 563 K This gives an ideal Carnot efficiency of 100 ×(1-563K/839K) = 33 % Thus the total solar insolation must be 1 GW/0.33 = 3 GW. The installation in Figure 9.4 is in California and from Figure 8.2 the average insolation can be estimated to be 225 W/m. The area needed to produce the necessary power is 1.3 x 10 m. For a circular array this corresponds to an area about 4 km in diameter. This is too large of an area. Why?See Answer
Q6:2. Problem 10.1 (10 pts) The power output in watts is given as P = (0.602 kg/m³)4 nv³ The velocity as a function of height isSee Answer
Q7:3. Problem 10.2 (10 pts) Area per turbine is (3.14) x (5 m) = 78.5 m² per turbine. The power per turbine will be P = 4.08 × 10³ W The average spacing of the wind turbines downwind will be 10 times the rotor diameter or 100 m and the crosswind spacing will be 3 times the rotor diameter or 30 m. Thus each turbine will occupy a land area of (30 m) x (100 m) = 3000 m². Thus, 1 km² square of land area will accommodate (10 m/km)/(3000 m²) = 333 turbines with a total output of 1.36 MW (b) From equation (9.3), P = 30.2 MW. This is more than 20 times the wind power output.See Answer
Q8:4. Problem 10.3 (10 pts) P = (0.602 kg/m )nAv. Solving for n givesSee Answer
Q9:EG-111 Technical Report Topic Assignments This list details the topic selected for your technical report by your student number. You may NOT chose your own report topic, and your topic may NOT be changed from this list. Topic 1: Types of fuel cells and their applicationsSee Answer
Q10:Scenario, Assignment Brief and Guidance: Scenario: You are an engineer working on a wind turbine "green energy" project for BCP City Council. Their wind turbine blades are not lasting as long as predicted, and in-service problems do not match predicted life from laboratory test results. You have been tasked with reviewing and evaluating a number of possible materials for the improved manufacture of wind turbine blades, so that they last longer and are more reliable. Blades have failed in the past because of a build-up of electromagnetic charge, excessive heat, corrosion, mechanical strain and failure. Assignment Brief:/nAssignment Brief: Activity 1: Some wind turbine blades have cracked, failed or twisted (reduced 'angle of attack' and hence performance) in-service in much shorter times than predicted. Using the data from your laboratory tests, prepare and present a report that compares and contrasts the following: • torsion test results of four materials (two metallic & two non-metallic) against theoretical results (you may use the theoretical data from APPENDIX 1: Material Shear Modulus Data) • beam deflection test results of four materials (two metallic & two non-metallic) against theoretical results (you may use the theoretical data from APPENDIX 2: Modulus of Elasticity Material Data) Evaluate any differences and suggest why real-world & laboratory test results for wind turbine blades could differ from theoretical data. NOTE: Include evidence, photos and results of your laboratory tests in your report. So that your audience can understand the context of your report, you will need to describe how the structures of the different materials relate to their properties. You will also need to refer to the types of degradation that are most common in the four materials, and how relevant that is to the wind turbine blade application. Use citation/references using the Harvard referencing system where relevant. Show and explain any formulae used and calculations.See Answer
Q11:Activity 2: Some failures in service were caused by a build-up of static electricity (due to electromagnetic hysteresis) and other failures by ther generation of heat (due to elastic hysteresis). Review both types of hysteresis for the materials in activity 1, discussing the level of risk for the above-mentioned failures and particularly for the conditions in service of wind turbine blades. Guidance: College VLE- Teaching Resources HN Global Engineering Science See also APPENDIX 3: Information Sources: Engineering Materials and their PropertiesSee Answer
Q12:Instructions: Need to write a discussion in 200 words on any 1 option. Support your discussion with facts, graphs, pictures and follow all the instructions in the file. Need to write 2 peer responses in 150 words each. Posts and opinions will be provided later.See Answer
Q13:Question 1 Please give your view of the role of solar energy in the United States electricity generation mix. Edit View Insert Format Tools Table 12pt ✓ Paragraph | B IU A T² V | 10 ptsSee Answer
Q14:D Question 2 Please explain why project management is so important a skill set to develop for the continued build out of this resource. Edit View Insert Format Tools Table 12pt ✓ Paragraph | B I U A 10 pts o v T² v |See Answer
Q15:Question 1 You want to convert solar energy into electricity, which of the following can you use? O Photovoltaic [PV] O Solar Thermal Electricity [STE] Concentrated Photovoltaic [CPV] O All of the above Question 2 You are analyzing the PV market, what factors should you consider? Components Prices (Module, Inverter, BOS, ... etc) O Installation and Labor cost O Soft cost (Design & Engineering, Permitting,,, etc) O All of the above 1 pts 1 ptsSee Answer
Q16:Question 7 The Inspector is responsible for: O Designing the PV system according to the local and national standards O Installing PV system according to the local and national standards · O Designing the PV system according to the local and national standards AND Installing 'V system according to the local and national standards O Reviewing the PV system's compliance with codes and standards Question 8 You want to be a PV installer, what certification should you get? O IREC and IEC O NABCEP O NEC 1 pts O UL 1 ptsSee Answer
Q17:Question 5 You are preparing a one-line electrical drawing for a grid-tied PV system with battery backup, which of the following is the right components order (starting from PV modules and ending at the utility Grid): O Inverter-disconnect-meter-PV array-battery O PV array-disconnect-inverter-meter-battery O PV array-battery-inverter-disconnect-meter O PV array-battery-meter-inverter-disconnect Question 6 The Installer is responsible for: 1 pts O Inspect PV system for code compliance 1 pts Designing the PV system according to the local and national standards Installing PV system according to the local and national standards O Designing the PV system according to the local and national standards AND Installing PV system according to the local and national standardsSee Answer
Q18:Question 11 Based on the data presented in both of the PV 2014 IEA roadmap and the STE 2014 IEA roadmap, which solar technology has greater solar market share? O STE is leading the global solar market and PV comes as second place O PV has greater global solar market share than STE O CPV is leading the global solar market The market of the solar technologies is equally split Question 12 Based on Question 11, what is the main reason that one technology outnumbered the other? 1 pts O STE is much simpler technology that uses mirrors and with larger plants it makes economical sense to be leading the solar market with cheaper initial cost O PV prices are going down and the development of new CSP still cannot compete with the low PV prices O CPV generates more per unit area power and it occupies less land space which makes it more economical choice to outnumber PV technology O Since the market is equally shared, that indicates that the prices are all the same for STE, CPV, and PV 1 ptsSee Answer
Q19:Question 9 A Commercial PV systems can fall into which of the following PV market segments? O Residential O Utility scale O Non-residential O All of above Question 10 Commercial PV systems are cheaper to install when compared to: O Residential O Utility scale O Non-residential O All of the above 1 pts 1 ptsSee Answer
Q20:Question 14 From the following video (that you watched in Lesson 1): Video: How Tokelau Switched to Solar Energy. Why diesel generators were used along with the PV array? O PV system is backed up by diesel generators when the sun is not available and batteries are fully discharged O For emergency loads only O To charge batteries when sun is not available O None of the above Question 15 Based on your answer for Question 14, what type of PV configuration is the final system? 1 pts Bimodal system with only battery as second energy source O Hybrid system with Diesel Generator and Battery back-up O PV grid-connected system O None of the above 1 ptsSee Answer

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