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  • Q1: 5. Which of these particle diagrams represents a sample of pure water? How can you tell? See Answer
  • Q2:Need help with this homework which is 6 summaries of 6 analytic chemistry journal readings from the American Chemical Society (ACS). For each summaries, only a paragraph is needed, like 250 words each. It has to be Analytical Chemistry journals. Here are the link: https://pubs.acs.org/action/showMostReadArticles? topArticlesType=recent&journalCode=ancham Choose any 6 articles from the above link and work on this assignmentSee Answer
  • Q3:Question 2 a) You work for an environmental laboratory conducting screening of wastewater for potential contaminants. The laboratory currently possesses a reverse-phase liquid chromatograph but is considering purchase of an ion chromatograph. Provide an argument for the laboratory's procurement officer that purchasing an ion chromatograph would extend the laboratory's analytical capabilities. Your answer should make use of appropriate annotated diagrams. b) You are an analytical chemist in a forensic laboratory. You have been tasked with analysing fire debris for volatile hydrocarbons that might be indicative of a chemical accelerant. i. Which mode of chromatography would you recommend for this purpose, and why? Justify your answer. ii. The evidence submitted is a swatch of carpet in a sealed container. How would you sample potential volatile hydrocarbons from this material? Justify your approach. c) Using media or internet sources, identify and describe a "real-world" problem in which gas chromatography, liquid chromatography, or ion chromatography was used to achieve separation of analytes in a mixture. See Answer
  • Q4:1. In a multiple dilution series, 20 μL of serum from tube 1 and 80 μL of diluent are added and mixed in tube 2. From tube 2, 10 µL is taken and added into 40 μL of diluent in tube 3. What is the dilution factor in tube 3?See Answer
  • Q5:2. A multiple dilution series was made. The sample was diluted 1:4, 1:2, 1:5, and 1:10. What is the final dilution in the last tube?See Answer
  • Q6:3. A multiple dilution series was made. The sample was diluted 1:2, 1:3, 1:4, and 1:5. The original concentration of the sample was 2400 mg/dL. What is the concentration of the sample in the last tube?See Answer
  • Q7:5. A five-fold dilution series of serum in saline is performed. If 5 dilutions are made, what is the serum dilution in the last tube?See Answer
  • Q8:6. A series of 5 two-fold dilutions of concentrated solution is to be done. If 4 mL of diluent is put into each tube, how much concentrated solution will be added to tube 2? (Assume tube 1 is straight/1:1).See Answer
  • Q9:7. If the results of a glucose determination was 60 mg/dL, and the original specimen had been diluted 1:5 and 1:5 again, what results should be reported?See Answer
  • Q10:8. A stock glucose standard has a concentration of 100 mg/dL. A 1:50 dilution of the standard is done. What is the concentration of the resulting dilution?See Answer
  • Q11:9. How much of a 1:25 dilution can be made with 4 mL of serum?See Answer
  • Q12:10. A white blood count is done on a blood sample that has been diluted 1:20. The number of cells counted in the sample is 202 cells/μL. What should be reported for the undiluted sample?See Answer
  • Q13:11. In a multiple dilution series, 10 mL of serum from tube 1 and 90 mL of diluent are added and mixed in tube 2. From tube 2, 10 mL is taken and added to 40 mL of diluent in tube 3. If the original concentration of the sample had been 50 mg/dL, what is the concentration in tube 3?See Answer
  • Q14:12. Matching: A serial dilution series is made where each tube is diluted 1:4. Tube 1 contains 1 mL of undiluted sample, which is added to diluent in tube 2 and so on. If the original concentration was 6142 mg/dL, what is the concentration in each tube? Match the correct concentration to each tube. Tube 1 = Tube 2 = Tube 3 = Tube 4 = Tube 5=See Answer
  • Q15:13. Matching: A multiple dilutions series is diluted as follows: Tube 1 = 1:1 Tube 2 = 1:4 Tube 3 = 1:3 Tube 4 = 1:5 Tube 5 = 1:2 Calculate the final dilution in tubes 2-5 and match them to the correct answer.See Answer
  • Q16:14) Predict the approximate chemical shift of the shaded protons in the following compounds a. C6H6 b. CH3COCH3 c. CH3OCH2CH3 d. CH3CH2CH=0 e. C6H5COOH f. CH3CH2Br See Answer
  • Q17:Determine the number of different kinds of protons in each compound a) CH3CH2CH2Cl b) CH3CH(Cl)CH3 c) CH3C(CH3)2CH2CH3 d) CH3CH(CH3)CH(CH3)2 See Answer
  • Q18:16. Predict the multiplicity for each shaded protons in the following compounds a. CH3CH2CCl2CH3 b. CH3CH(CH3)OH c. CH3CH(CH3)CH3 d. CH3CH2COOCH2CH3 See Answer
  • Q19:Q4. This question is about acidic solutions. (a) The acid dissociation constant, Ka, for ethanoic acid is given by the expression [CH₂COO-][H+] [CH₂COOH] Ka -3 The value of K₂ for ethanoic acid is 1.74 x 10-5 mol dm-³ at 25 °C A buffer solution with a pH of 3.87 was prepared using ethanoic acid and sodium ethanoate. In the buffer solution, the concentration of ethanoate ions was 0.136 mol dm¯³ Calculate the concentration of the ethanoic acid in the buffer solution. Give your answer to three significant figures. Concentration of acid - mol dm 3 (b) In a different buffer solution, the concentration of ethanoic acid was 0.260 mol dm-³ and the concentration of ethanoate ions was 0.121 mol dm¯ -3 A 7.00 × 10-3 mol sample of sodium hydroxide was added to 500 cm³ of this buffer solution. Calculate the pH of the buffer solution after the sodium hydroxide was added. Give your answer to two decimal places. (3)/n(C) A buffer solution with a pH of 4.5 is made by dissolving x g of sodium propanoate (C₂H5 COONa) in a solution of propanoic acid. The final volume of the buffer solution is 500 cm³, and the final concentration of the propanoic acid is 0.50 mol dm-3 .The value of K₂= 1.74 × 10-5 mol dm-3 at 25 °CSee Answer
  • Q20:Based on the information below, propose a structure for the compound. Use the infrared spectrum to identify potential functional groups and use the ¹H NMR spectrum to identify the various protons present. Molecular Formula: CH,NCI₂ Hint: The ring system is trisubstituted at position 1, 2 and 4. Nujol mul 31863 3420.2 3310.3 300 MHz CDCI, C www.ger 7.250 7240 2851.1 29148 7000 Wavenumber appar DE мм Chach 7.000 618.4 43713 481.5 D₂O Shake 2:00 309.8 402.4 45 40 35 Chemical Shift (ppm) 294.4 6.700 6475 Chemical Shipp 822 1130.4 h045.5 Veed 1700 26 1823 648 814.1 6650See Answer

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