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Q1: A 30 ft long simply supported beam with full lateral support along the compression flange supportsa moving concentrated load of 40 kip. Estimate beam weight at 60 plf. Select the lightest sectionSee Answer
Q2: 4-62. If the 50 mm diameter supporting rods are made from steel, determine the average normal stress developed in each rod when P = 450 kN. 4-63.If the supporting rods of equal diameter are made from A992 steel, determine the required diameter to the nearest 3.175 mm of each rod when P = 450 kN. The allowable normal stress of the steel is o allow = 170 MPa. See Answer
Q3: 3.2-2 A PL 3/8 x 6 tension member is welded to a gusset plate as shown in Figure P3.2-2. The steel has a yield stress Fy = 50 ksi and an ultimate tensile stress Fu = 65 ksi. Assume that Ae = A̟g and compute a. the design strength for LRFD b. the allowable strength for ASD See Answer
Q4: Please select the following types of bolts we have discussed in our lecture: O a. Turned Bolts O b. Canadian Bolts c. High-Strength Friction Grip Bolts d. Ribbed Bolts O e. Black BoltsSee Answer
Q5: Which of the following connections did we NOTdiscuss in class: a. Shear connections O b. Connecting angles O c. Moment connections O d. Effective stress connections Connecting platesSee Answer
Q6:2. An L5x5x1/2 in tension is connected to the structure by two longitudinal 12" welds, with one weld 3" long and the other weld 6" long. Calculate the shear lag factor for the connection. (5 points) 6" 3"See Answer
Q7:3. Given the continuous beam shown below, which span or spans should be loaded with a uniform distributed load to produce a maximum moment at support B? (5 points) A ΑΔ SPAN 1 20 ft TYP. B SPAN 2 C SPAN 3 DSee Answer
Q8:4. What is local buckling and how does it differ from global buckling? (5 points)See Answer
Q9:5. Draw an example of each global buckling limit state and an example of local buckling in the flange and local buckling in the web. (5 points)See Answer
Q10:6. A W12x53 has been selected as a compression member for a single-story building design. The member is made of A992 Steel. The member is 20' long, fixed at the bottom and pinned at the top in both axes. The member is braced against flexure at the midpoint in the minor axis only. The member is braced against torsion in both axes at the midpoint (In other words, flexural unbraced length is greater than or equal to the torsional unbraced length) If the DL= 150 kips, what is the maximum LL that can be applied to the column? Use LRFD and ASCE 7-22 Load Combos. (25 points)See Answer
Q11:7. A tension member is subjected to the following unfactored loads: DL = 220 kips and LL = 185 kips. Select the lightest WT7X__ tension member that can carry the load given the below bolt pattern. Steel is A36 grade. The bolt diameter is 7/8-inch. Assume that block shear does not control, so you only need to check yielding of the gross area and rupture on the net area. (HINT: Design will go faster if you find the minimum required gross area of steel, Ag). (25 points) 3 3 3 1.5" 0000 0000See Answer
Q12:8. An office building has the following floor plan: 1 2 A B C Beam A1-A2 D Girder A1-G1 10 ft 15 ft 15 ft E F G 10 ft 25 ft (TYP) 5 ft The office building dead load consists only of a concrete slab 6" thick and 10 psf of additional unfactored dead load for HVAC. The slab is made of normal weight concrete (150 pounds per cubic foot). The floor must carry a standard office live load of 80 psf. a) Find the factored floor load in psf (5 points) b) Find the reactions of the beams acting on Girder A1-G1 (10 points) c) Find the reactions of Girder A1-G1 on Columns A1 and G1 (10 points) 5 ftSee Answer
Q13:5. Identify the zero force members in the truss shown below: F E N TOT B mmmm M C слSee Answer
Q14:6. Select the lightest steel wide-flange section (W33 shape) for the beam shown. Assuming that flexure controls the design (moment controls the design). Do not consider beam weight. The allowable bending stress is 30 ksi (Fb = 30 ksi). Given: E = 29,000 ksi R₁ = 55.25 kips +55.25 0 50 kips + 18'-0" -12.75 30-0 -1 kip/ft +37.25 832.5 B Load diagram R = 42.75 kips 0 Shear (V) diagram (kips) -42.75 Moment (M) diagram 0 (fl-kips)See Answer
Q15:8. Draw the beam that represents the loading diagram shown below. Indicate the support types, load types and their points of application. BEAM SHEAR 0 MOMENT BEAM SHEAR 0 MOMENT 0See Answer
Q16:Q3. (5 @ 10 = 50 pts.) Show Calculations. Failure to show calculations and FBD will result in a grade of zero. 1. Draw the V- and M-diagrams, providing numerical values on the diagrams at points of change in shear and at all points or maximum moment. Assume the beam to be weightless. Identify maximum moment and shear in the beam. V-Dig. M-Dig. 25 k 3 14 kips B 3. 8 kips C-080 63 k 10 kipsSee Answer
Q17:3. For the beam shown. Determine: A. The maximum tensile and compressive stresses due to bending B. shearing stress at the neutral axis. Given Ix = 101.5 in N.A 5" Beam cross-section 2.35" 4.65* Deflected shape v (k) GAR 6MM M (k-ft) G 18 k 18 1011 72 18 k 18 6* BAR 5See Answer
Q18:4. A W 10 X 49 is used as a 40-ft-long column. The column is assumed fixed at the bottom, pined top and all other connections as pin connection, and its weak axis is braced at a point 22 ft up from the lower end as shown. Determine the allowable load capacity of the W 10 x 49. Use ASTM A992 steel with Fy = 50 ksi. Given: For W 10 x 49, Area = 14.4 in², rx = 4.35 in, and ry = 2.54 in 18 ft 22 ft W 10 x 49 ColumnSee Answer
Q19: PART B-STEEL MATERIAL (40 marks) B. You need to use your student ID to get some parameters. No marks for wrong input values. A simply supported steel beam is subjected to a point load, P, at the middle of the span. L/2 L/2 Note, some data is given based on your student ID. a = the last two digits of your student ID. For example, if ID=12345678, use a-78 to get the below information • The whole span of the beam, L (m) = 8 +0.05 x a For example, L = 8 +0.05 × 78 = 11.9 m The point load (P) is the critical load combination, and it provides the lateral restraint for the beam. The loads acting on the beam are: Dead load, G (kN) = 80 +0.1 x a (The self-weight is already included in this dead load calculation) • Live load, Q (kN) = 10 • Upward wind load, W. (kN) = 60 Answer the following questions: 1. Determine the critical shear force and bending moment acting on the beam. (10 marks) 2. Check whether or not the given section in Table 1 satisfies the ultimate limit state for flexure. Knowing that the beam is not fully lateral restrained for bending, and the shear capacity of the beam is adequate. (30 marks) Table 1. The steel section for Part B The last digit of your student ID 0 1 2 3 4 5 P 6 7 8 9 UB section 310 UB 40.4 530 UB 92.4 530 UB 82.0 460 UB 82.1 460 UB 74.6 460 UB 67.1 360 UB 56.7 360 UB 50.7 360 UB 44.7 310 UB 46.2See Answer
Q20:Refer to the sample drawings "NREL IBRF" and textbook to answer the following questions - 1. (3 pts) Given exactly the same shapes and load, but two options for material, which material will have a higher stress applied and why? Refer to the equation we described in class. 10 ft. Homework #4 200 lbs II Steel MarshmallowSee Answer

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