3. Problem 10.2 (10 pts) Area per turbine is (3.14) x (5 m) = 78.5 m² per turbine. The power per turbine will be P = 4.08 × 10³ W The

average spacing of the wind turbines downwind will be 10 times the rotor diameter or 100 m and the crosswind spacing will be 3 times the rotor diameter or 30 m. Thus each turbine will occupy a land area of (30 m) x (100 m) = 3000 m². Thus, 1 km² square of land area will accommodate (10 m/km)/(3000 m²) = 333 turbines with a total output of 1.36 MW (b) From equation (9.3), P = 30.2 MW. This is more than 20 times the wind power output.