Consider the following equilibrium:

PC15(g) → PC13(g) + Cl₂(g)

What is the value of the equilibrium constant K(T) at T = 400 K? At 25 °C:

∆H (PC15,g) = -374.9 kJ/mol ;

∆H°(PCl3,g) = -287.0 kJ/mol ; Sm (PCl3,g)

Sm (PC15,g) = 364.6 J / (K mol)

311.78 J/(K mol)

Smᵒ(Cl₂,g) = 223.07 J / (K mol)

O a. 2.6 × 10-3

O b.0.0

O c. 8.5 x 103

O d. 3.05 x 10-7

O e. 5.03 x

10-4