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**Q1:**The below Table shows the specification required for a gate drive circuit and the driven MOSFETs in a buck converter. Answer the following Questions 下表は,降圧チョッパ回路に用いるゲートドライブ回路と駆動される MOSFET の仕様である。 以 下の問に答えよ。 DC input voltage DC output voltage DC output current Switching frequency Gate resistor Gate driving voltage Drain-to-source voltage Drain current On-state resistance Forward transfer conductance Threshold voltage E Vout Lout R₂ E Vds Is Ran US Vih Cias Input capacitance Cos Output capacitance Reverse transfer capacitance Cras 100 V 50 V 10 A 20 kHz 10 Ω +10 V 250 V 30 A 100 m 20 S 5 V 10,000 pF 1000 pF 100 pF 1. Find the rise time Tr and the fall time Tf. 上昇時間 Tr と降下時間 Tf を求めよ。 2. Find the di/dt across the MOSFET in turn-on and turn-off transitions. MOSFET がターンオン・ターンオフする際の di/dt を求めよ。 3. It is requested to reduce the dv/dt to a half in a turn-on transition without any change in the turn-off transition. Answer the possible ways. ターンオフ時には影響を与えずに, ターンオン時のdv/dt を2倍にしたい。 可能な方法を答え よ。See Answer**Q2:**Fig.2 shows a snubber circuit. Answer the following Questions 図2 は, スナバ回路の回路図である。以下の問に答えよ。 1. Exprain the main function of the resisitor R. 抵抗器 R の主目的を述べよ。 2. Find the required capacitance of C to suppress the dv/dt less than 1 kV / μs where the initial collector current is 2000A before the turn-off. ターンオフ前のコレクタ電流が 2000A の時, dv/dt を 1kV/μs 以下に抑制するため のCの静電容量を求めよ。 3. Draw the turn-off waveform of the collector-to-emitter voltage of the IGBT where the di/dt is assumed to be 10kA / μs and the final voltage is 2000 V. IGBT のターンオフ時の di/dt を 10kA/μs, 最終電圧を 2000 V として, コレクタ・ エミッタ間電圧の波形を描け。 4. Find the fall time and voltage where the collector current reach zero. 降下時間とコレクタ電流が零になった時の電圧を求めよ。 DV R Fig. 2 Snubber circuit.See Answer**Q3:**Fig.2 shows a snubber circuit. Answer the following Questions 図2は, スナバ回路の回路図である。 以下の問に答えよ。 1. Exprain the main function of the resisitor R. 抵抗器 R の主目的を述べよ。 2. Find the required capacitance of C to suppress the dv/dt less than 1 kV/ us where the initial collector current is 2000A before the turn-off. ターンオフ前のコレクタ電流が 2000 A の時, dv/dt を 1kV/μs 以下に抑制するため のCの静電容量を求めよ。 3. Draw the turn-off waveform of the collector-to-emitter voltage of the IGBT where the di/dt is assumed to be 10kA/ μs and the final voltage is 2000 V. IGBT のターンオフ時の di/dt を 10kA/μs, 最終電圧を 2000 V として, コレクタ・ エミッタ間電圧の波形を描け。 4. Find the fall time and voltage where the collector current reach zero. 降下時間とコレクタ電流が零になった時の電圧を求めよ。 D空 R Fig. 2 Snubber circuit./nThe below Table shows the specification required for a gate drive circuit and the driven MOSFETs in a buck converter. Answer the following Questions 下表は, 降圧チョッパ回路に用いるゲートドライブ回路と駆動される MOSFET の仕様である。 以 下の問に答えよ。 DC input voltage DC output voltage DC output current Switching frequency Gate resistor Gate driving voltage Drain-to-source voltage Drain current On-state resistance Forward transfer conductance Threshold voltage Input capacitance Output capacitance Reverse transfer capacitance E Vont Lout R₂ E Vas Ia Ran Uf- Vih Ci Coss Cras 100 V 50 V 10 A 20 kHz 10 2 +10 V 250 V 30 A 100 m2 20 S 5 V 10,000 pF 1000 pF 100 pF 1. Find the rise time Tr and the fall time Tf. 上昇時間 Tr と降下時間 Tf を求めよ。 2. Find the di/dt across the MOSFET in turn-on and turn-off transitions. MOSFET がターンオン・ターンオフする際の di/dt を求めよ。 3. It is requested to reduce the dv/dt to a half in a turn-on transition without any change in the turn off transition. Answer the possible ways. ターンオフ時には影響を与えずに, ターンオン時のdv/dt を2倍にしたい。 可能な方法を答え よ。See Answer**Q4:**WINCH DRIVE USING SINGLE-PHASE CONTROLLED RECTIFIER A Separately-Excited DC Motor is driving a Winch Drum through a 1:10 speed reduction gearing system. The diameter of cable drum is 40 cm. The motor is a 367 Frame Size whose parameters are: 230 V, 30 hp, 1150 RPM, 108 A, 0.0963 armature resistance. The motor armature inductance is assumed large enough such that the armature current is assumed ripple-free. The motor is driven from a 240 V, 50 Hz sinusoidal source through a single-phase controlled rectifier. The motor field current is assumed constant at rated value. (1) Is the motor capable of raising the load at rated loading conditions? If not, calculate the maximum linear velocity of the load while raising up. Then evaluate the THDF of the supply current and the input power factor of the system. Assume constant rotational loss. (2) If the motor is to raise the load at rated conditions (i.e., torque and speed), what would you suggest? In this case calculate the possible linear velocity of the system while raising up. (3) If the motor is to lower the load at the same raising speed without overloading, calculate the firing angle required for this purpose, and evaluate the THDF of the supply current and the input power factor of the system. (4) If the motor is to hold the load at standstill, what is the value of the load current to do so? Can you comment on such a situation?See Answer**Q5:**Consider the DC Motor control set-up in Fig. 1. VDC V (D) Fig. 1. H-bridge drive system for DC motor DC Motor 1) Considering bipolar switching, compute the average value of the voltage across the terminals of the DC motor as a function of the duty cycle V, (D). Justify your answer using a diagram of the circuit and the step-by-step averaging procedure.See Answer**Q6:**2) Compute the total electromagnetic torque T, and the rotor speed when the duty cycle is equal to 0.8 in the following three cases. a) The separately excited connection in Fig. 2. Consider. Voc=200V, R₂ = 10, La = 80mH, Lm = 2H,J = 0.005 kgm², B₁ = 0.0015 Nm/rad, i, = 1A. Ra ka Tue VDC Fig. 2. H-bridge drive system for separately excited DC motor 3 b) The shunt excited connection in Fig. 2. Consider: VDC Vpc = 200V, R₂ = 10, La = 80mH, Lm = 2H,J = 0.005 kgm², R, = 2000, L = 20H, B₁ = 0.0015 Nm/rad. + Va 4 R₂ Luly M000 4 R₂ Fig. 2. H-bridge drive system for a shunt DC motor V₁ [10]See Answer**Q7:**2. A boost converter is used to step up 25V into 40V. The switching frequency of its transistor is 1kHz, and the load resistor is 10092. Compute a) The current ripple when the inductor is 30mH. b) The average current of the load c) The power delivered by the sourceSee Answer**Q8:**3. A buck-boost converter with an input voltage of 40V is used to regulate the load voltage in the range of 10 to 80V. The on-time of the transistor is always fixed at 0.1ms and the switching frequency is adjusted to regulate the load voltage. Compute the range of switching frequency.See Answer**Q9:**Problem-1 [40 Points] Two transistors Tr₁ and Tr2 are parallel connected, as shown in the following figure. For a forward-biased dc steady-state operation, it is known that the total load current is in=200/A/, the collector-emitter voltage of the first transistor is VCE1 =1.5/V/, and of the second transistor is VCE2=1.1/V/. The resistances series connected to transistors have the value of RE₁= 10/m/ and RE2=20/m2/, respectively. For each transistor calculate the collector's current value (ic₁ and icz), and the difference in percent of the collector currents as referred to the total current (((ic₁ - icz)/iT) x 100). It is added that to solve the problem, the base current is neglected. iT Tr.4 (B1) REA LEA ict CEA E lica. Q CEZ E₂ REZ LEZ Tr.2 (B2) Fig. 1: Transistors in Parallel Rc VccSee Answer**Q10:**Problem-2 [150] In the figure shown below, the transistor T, is used as a switch for the load resistance R₁. The circuit data are the following: the voltage of the main de source,Vcc= 200.006/V/; the voltage of the base de source, V₁= 3.5 /V/; the load resistance, R₁= 1.98006 /2/; and the resistance of the base circuit, RB = 0.0625 /22/. V₂ RB is BE ic (6) ACE Re + Vcc 1/nComments: The values shown for the main de voltage source and the load resistance do not look too realistic. The reason is to have the data of the shown circuit in agreement with the waveforms that follow. The switch is shown on the base circuit to model the control process that is present on the base circuit. For a cycle of the transistor operation, the waveforms for different quantities are shown in the attached Figure 8-10. The length of different time intervals shown in the figure is as follows: ta = 0.5 /μs/; t₁= 1 /µs/; ts = 5 /µs/; tf = 3 /us/. It is also specified that the signal frequency is fs= 10 /kHz/ and that the duty cycle is D = 50% (Here the duty cycle is defined as the ratio of the time length along which the base signal is present to the total time length of a cycle. With the data shown in Figure 8-10, the duty cycle is represented as: D /%/= ((ton+ tn)/T) x 100)./n200/vl 2/V] =VCE(sat) 1001A=Ics 3/MA/= ICEO ·0 8/A/= ¹8s -3/V/ = V₁E(San counted as t=0 karte & H. ig 1 VBE tn 1 +-+-+- •T = 1/₂ to Figure 8-10 Waveforms of transient switch./nFor the given circuit and its operation, calculate the value of: a) The energy consumed (lost) within the transistor, due to the collector current during the initial turn-on time-interval, that is, for 0 ≤t≤ta. b) The same quantity as in a) during the final turn-on time-interval, that is, for ta ≤ t ≤ton. c) The same quantity as in a) during the full conduction time-interval, that is, for ton ≤ t ≤ (ton + tn + ts). d) The same quantity as in a) during the initial turn-off time-interval, that is, for (ton + tn + ts) ≤t≤ (ton + tn + toff). e) The same quantity as on a) during the full turn-off time interval, that is, for (ton + tn + toff) ≤ t ≤ T. f) The total energy and the corresponding average power consumed (lost) within the transistor along an operation cycle, due to the collector current. g) The energy and the corresponding average power supplied by the base voltage source VB along an operating cycle. These correspond to the energy and the average power consumed (lost) within the transistor and in the base circuit resistance, R₁. h) The total energy and the corresponding average power consumed (lost) per transistor, that is, due by both the collector and the base current, including the energy and the corresponding average power lost in the base circuit resistance Rb./nj) i) For one cycle, the total energy and the corresponding average power supplied to the circuit by the main voltage source, Vcc and by the base voltage source VB. For one cycle calculate the total energy and the corresponding average power consumed by the load resistance R₁. For this purpose, you must use the load resistance R₁'s value and the corresponding collector current. k) Calculate the following difference: (total energy defined in (i)) minus (total energy defined in (h)). The same difference can be defined by using the corresponding average powers. Compare the difference obtained here with the values obtained in (j). 1) The circuit efficiency in percent, counting the total energy or the corresponding average power supplied by both, the main and the base de source, and the total energy or the corresponding average power lost in the transistor and in the base power resistance Rp. For the same purpose, it can be counted the total energy or the corresponding average power supplied by the main and base de sources and the total energy or the corresponding average power absorbed by the load resistance R₁. m) Along an operation cycle, plot the instantaneous power carried by the transistor, counting only the collector current. On the graph clearly specify the value for the maximum and minimum value of the instaneous power and the corresponding moment in time when each of these is reached.See Answer**Q11:**Problem-1 [40 Points] Two transistors Tr₁ and Tr2 are parallel connected, as shown in the following figure. For a forward-biased de steady-state operation, it is known that the total load current is iT=200/A/, the collector-emitter voltage of the first transistor is VCE1 =1.5/V/, and of the second transistor is VCE2=1.1/V/. The resistances series connected to transistors have the value of RE1- 10/m/ and RE2=20/m2/, respectively. For each transistor calculate the collector's current value (ic and icz), and the difference in percent of the collector currents as referred to the total current (((ici — İcz)/iT) x 100). It is added that to solve the problem, the base current is neglected. ir Tr.4 (B1) REA L'EL ica CI CEA E lica. + NCEZ Tre REZ AEZ (B2) Fig. 1: Transistors in Parallel Rc VccSee Answer**Q12:**Problem-1 [40 Points] Two transistors Tr₁ and Tr2 are parallel connected, as shown in the following figure. For a forward-biased de steady-state operation, it is known that the total load current is iT=200/A/, the collector-emitter voltage of the first transistor is VCE1 =1.5/V/, and of the second transistor is VCE2=1.1/V/. The resistances series connected to transistors have the value of RE1- 10/m/ and RE2=20/m2/, respectively. For each transistor calculate the collector's current value (ic and icz), and the difference in percent of the collector currents as referred to the total current (((ici — İcz)/iT) x 100). It is added that to solve the problem, the base current is neglected. ir Tr.4 (B1) REA L'EL ica CI CEA E lica. + NCEZ Tre REZ AEZ (B2) Fig. 1: Transistors in Parallel Rc Vcc/nProblem-1 [40 Points] Two transistors Tr₁ and Tr2 are parallel connected, as shown in the following figure. For a forward-biased de steady-state operation, it is known that the total load current is iT=200/A/, the collector-emitter voltage of the first transistor is VCE1 =1.5/V/, and of the second transistor is VCE2=1.1/V/. The resistances series connected to transistors have the value of RE1- 10/m/ and RE2=20/m2/, respectively. For each transistor calculate the collector's current value (ic and icz), and the difference in percent of the collector currents as referred to the total current (((ici — İcz)/iT) x 100). It is added that to solve the problem, the base current is neglected. ir Tr.4 (B1) REA L'EL ica CI CEA E lica. + NCEZ Tre REZ AEZ (B2) Fig. 1: Transistors in Parallel Rc Vcc/nProblem-1 [40 Points] Two transistors Tr₁ and Tr2 are parallel connected, as shown in the following figure. For a forward-biased de steady-state operation, it is known that the total load current is iT=200/A/, the collector-emitter voltage of the first transistor is VCE1 =1.5/V/, and of the second transistor is VCE2=1.1/V/. The resistances series connected to transistors have the value of RE1- 10/m/ and RE2=20/m2/, respectively. For each transistor calculate the collector's current value (ic and icz), and the difference in percent of the collector currents as referred to the total current (((ici — İcz)/iT) x 100). It is added that to solve the problem, the base current is neglected. ir Tr.4 (B1) REA L'EL ica CI CEA E lica. + NCEZ Tre REZ AEZ (B2) Fig. 1: Transistors in Parallel Rc Vcc/nProblem-1 [40 Points] Two transistors Tr₁ and Tr2 are parallel connected, as shown in the following figure. For a forward-biased de steady-state operation, it is known that the total load current is iT=200/A/, the collector-emitter voltage of the first transistor is VCE1 =1.5/V/, and of the second transistor is VCE2=1.1/V/. The resistances series connected to transistors have the value of RE1- 10/m/ and RE2=20/m2/, respectively. For each transistor calculate the collector's current value (ic and icz), and the difference in percent of the collector currents as referred to the total current (((ici — İcz)/iT) x 100). It is added that to solve the problem, the base current is neglected. ir Tr.4 (B1) REA L'EL ica CI CEA E lica. + NCEZ Tre REZ AEZ (B2) Fig. 1: Transistors in Parallel Rc Vcc/nProblem-1 [40 Points] Two transistors Tr₁ and Tr2 are parallel connected, as shown in the following figure. For a forward-biased de steady-state operation, it is known that the total load current is iT=200/A/, the collector-emitter voltage of the first transistor is VCE1 =1.5/V/, and of the second transistor is VCE2=1.1/V/. The resistances series connected to transistors have the value of RE1- 10/m/ and RE2=20/m2/, respectively. For each transistor calculate the collector's current value (ic and icz), and the difference in percent of the collector currents as referred to the total current (((ici — İcz)/iT) x 100). It is added that to solve the problem, the base current is neglected. ir Tr.4 (B1) REA L'EL ica CI CEA E lica. + NCEZ Tre REZ AEZ (B2) Fig. 1: Transistors in Parallel Rc VccSee Answer**Q13:**EXERCISE 1: Closed-Loop Controller Design and Simulation of H-bridge DC/AC Inverter Use Matlab/Simulink. You can use SimPower or Simscape libraries to simulate components needed in power electronics. Key elements that you need to simulate an H-bridge DC/AC Converter as shown in the figure above: • Four Mosfets • One Inductor One Capacitor One Resistor • DC Voltage Supply PWM Generator Other elements needed to run the simulation (not essential in the converter operation) L1 000 DC Supply Q1 Q2 TAT The preliminary design parameters are: Q3 Q4 -Vm=d(t)V de- -lout" C1 R1See Answer**Q14:**EXERCISE 2: Closed-Loop Controller Design and Simulation of H-bridge DC/AC Inverter with PV Objectives: - Getting familiar how a PV source operates when interfaced with an H-bridge PV Inverter Author: Babak Parkhideh, PhD You need to take the "PV Array" block from the Simulink Library. Choose the SolarWorld Sunmodule Plus SW 250 mono Black from the Module data drop-down list. We use only one panel throughout the lab. First, consider the nominal operating points defined in the PV panel datasheet (mentioned in the Simulink interface too). Use the nominal parameters you have chosen in Exercise 1. You need to consider a DC link capacitor in parallel to the PV panel. Make sure the DC link voltage ripple in less than 2V at the nominal operating point. Construct the closed-loop feedback simulation model of the inverter interfacing with the PV array. If you have constructed the model in the previous labs, update the model. You can use the architecture shown below. Use the PID block in Simulink. Choose a proper Time Domain you have worked with, Continuous vs. Discrete. + Note that the modulation index must be sinusoidal to generate a 60Hz output. Make sure the compensator output is multiplied by Sin(2pi60t). Or, use the dq transformation or similar to extract the rms or mean value of the current. Multiply the current controller output by Sin(2pi60t). DC Link Voltage- Reference (PV Voltage) PID lac-ret Revised 10/04/2021 Duty cycle Page 4 of 6 Current Controller PWM PV Inverter DC link Voltage, VocSee Answer**Q15:**Implement an H-bridge inverter and all the necessary elements according to the operating point in Simulink. If you have the model from previous lab modules, open your Simulink model.See Answer**Q16:**Open the APP "Linearization Manager"See Answer**Q17:**Define your input (duty cycle value) and output (i.e. output current). When you select the measurement by highlighting its trace, the INSERT ANALYSIS POINTS will be enabled. Choose the input perturbation and Output MeasurementSee Answer**Q18:**1. (a) In what conditions do you use RC and LC filters in power supply design? Why? (b) (b) Define time constant, rising time and settling time. Explain the importance of these parameters in first order and second order systems.See Answer**Q19:**2.18(Page.31) 2. A voltmeter with a range of 0 to 100 V reads 2 V when the leads are shorted together. The manufacturer claims an accuracy of ±4% of full scale. Estimate the maximum error when reading a voltage of 80 V in both volts and as a percentage of reading. If the voltmeter is adjusted so that the reading when the leads are shorted together is 0 V, estimate the maximum percent error when reading 80 V.See Answer**Q20:**2.41 (page.34) 3. A thermometer, initially at a temperature of 75°F, is suddenly immersed into a tank of water with a temperature of 180°F. The time constant of the thermometer is 4 S. What are the values of rise time and the 90% response time? Assume this to be a first order system.See Answer

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